{"id":1021,"date":"2017-11-07T16:48:32","date_gmt":"2017-11-07T21:48:32","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/telg1001\/?p=1021"},"modified":"2026-01-02T10:37:24","modified_gmt":"2026-01-02T15:37:24","slug":"1eva2016ti_t3-lti-dt-hn-por-bloques-y-respuesta-de-paso","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/ss-1eva\/1eva2016ti_t3-lti-dt-hn-por-bloques-y-respuesta-de-paso\/","title":{"rendered":"1Eva2016TI_T3 LTI DT h[n] por bloques y respuesta de paso"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">1ra Evaluaci\u00f3n I T\u00e9rmino 2016-2017. 30\/Junio\/2016. TELG1001<\/h2>\n\n\n\n<p><strong>Tema 3<\/strong>. (28 puntos) El esquema del diagrama de bloques en el dominio de tiempo discreto que describe la entrada-salida de un sistema LTI-DT causal, es el siguiente:<\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"503\" height=\"190\" src=\"http:\/\/blog.espol.edu.ec\/algoritmos101\/files\/2017\/11\/1E2016TI_T3_LTID_diag.png\" alt=\"1E2016TI_T3 LTI D diagrama\" class=\"wp-image-20168\" \/><\/figure>\n\n\n\n<p>a. Determine la ecuaci\u00f3n de diferencias de coeficientes constantes que permite relacionar la entrada-salida del referido sistema causal.<\/p>\n\n\n\n<p>b. Determinar la respuesta impulso h[n] e indique si el sistema es con memoria o sin memoria, BiBO estable o no. Justifique debidamente su respuesta.<\/p>\n\n\n\n<p>c. Determinar el valor de la respuesta de paso s[n] para cuando n\u2192\u221e<\/p>\n","protected":false},"excerpt":{"rendered":"<p>1ra Evaluaci\u00f3n I T\u00e9rmino 2016-2017. 30\/Junio\/2016. TELG1001 Tema 3. (28 puntos) El esquema del diagrama de bloques en el dominio de tiempo discreto que describe la entrada-salida de un sistema LTI-DT causal, es el siguiente: a. Determine la ecuaci\u00f3n de diferencias de coeficientes constantes que permite relacionar la entrada-salida del referido sistema causal. b. Determinar [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-ss-ejercicios","format":"standard","meta":{"footnotes":""},"categories":[178],"tags":[179,182,183],"class_list":["post-1021","post","type-post","status-publish","format-standard","hentry","category-ss-1eva","tag-diagrama-de-bloques","tag-lti-dt","tag-transformada-z"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/1021","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=1021"}],"version-history":[{"count":4,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/1021\/revisions"}],"predecessor-version":[{"id":20171,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/1021\/revisions\/20171"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=1021"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=1021"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=1021"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}