{"id":1027,"date":"2016-09-26T06:42:18","date_gmt":"2016-09-26T11:42:18","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/estg1003\/?p=1027"},"modified":"2026-04-05T16:26:03","modified_gmt":"2026-04-05T21:26:03","slug":"2eva2012tiii_t3-fiec-autocovarianza","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/stp-2eva\/2eva2012tiii_t3-fiec-autocovarianza\/","title":{"rendered":"2Eva2012TIII_T3 FIEC autocovarianza"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">2da Evaluaci\u00f3n III T\u00e9rmino 2012-2013. Marzo 20, 2013. FIEC03236<\/h2>\n\n\n\n<p><strong>Tema 3<\/strong> (40 puntos). Dada la figura, asuma que el proceso es estoc\u00e1stico:<\/p>\n\n\n\n<figure class=\"wp-block-image alignright\"><img decoding=\"async\" src=\"http:\/\/blog.espol.edu.ec\/algoritmos101\/files\/2017\/07\/2Eva_IIIT2012_T3_01.png\" alt=\"\" \/><\/figure>\n\n\n\n<p>Siendo <strong>X<\/strong>(t) = <strong>A<\/strong>*g(t),&nbsp; donde <strong>A<\/strong> es una variable aleatoria que toma los valores -1 y +1 con igual probabilidad, determine:<\/p>\n\n\n\n<p>a) La funci\u00f3n (pmf) probabilidad de masa de <strong>X<\/strong>(t)<\/p>\n\n\n\n<p>b) E[<strong>X<\/strong>(t)], Var[<strong>X<\/strong>(t)]<\/p>\n\n\n\n<p>c) La pmf conjunta de <strong>X<\/strong>(t) y <strong>X<\/strong>(t+d)<\/p>\n\n\n\n<p>d) La C<sub>X<\/sub>(t, t+d), d&gt;0<\/p>\n\n\n\n<p><strong>R\u00fabrica<\/strong>: cada literal (10 puntos)<\/p>\n","protected":false},"excerpt":{"rendered":"<p>2da Evaluaci\u00f3n III T\u00e9rmino 2012-2013. Marzo 20, 2013. FIEC03236 Tema 3 (40 puntos). Dada la figura, asuma que el proceso es estoc\u00e1stico: Siendo X(t) = A*g(t),&nbsp; donde A es una variable aleatoria que toma los valores -1 y +1 con igual probabilidad, determine: a) La funci\u00f3n (pmf) probabilidad de masa de X(t) b) E[X(t)], Var[X(t)] [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-stp-ejercicios","format":"standard","meta":{"footnotes":""},"categories":[210],"tags":[215],"class_list":["post-1027","post","type-post","status-publish","format-standard","hentry","category-stp-2eva","tag-autocorrelacion"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/1027","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=1027"}],"version-history":[{"count":4,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/1027\/revisions"}],"predecessor-version":[{"id":23502,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/1027\/revisions\/23502"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=1027"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=1027"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=1027"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}