{"id":1047,"date":"2016-10-26T07:10:24","date_gmt":"2016-10-26T12:10:24","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/estg1003\/?p=1047"},"modified":"2026-04-05T16:33:41","modified_gmt":"2026-04-05T21:33:41","slug":"3eva2012tiii_t6-fiec-potencia-media","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/stp-3eva\/3eva2012tiii_t6-fiec-potencia-media\/","title":{"rendered":"3Eva2012TIII_T6 FIEC potencia media"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">3ra Evaluaci\u00f3n III T\u00e9rmino 2012-2013. Abril 19, 2013. FIEC03236<\/h2>\n\n\n\n<p><strong>Tema 6<\/strong> (20 puntos). Sea <strong>X<\/strong>(t) un proceso normal y estacionario, con media 0 y densidad espectral:<\/p>\n\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> S_X = \\frac{2}{4 + \\omega ^2} <\/span>\n\n\n\n<p>Y sea <strong>Y<\/strong>(t) la respuesta de un sistema lineal a la entrada <strong>X<\/strong>(t), siendo:<\/p>\n\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> H(\\omega) = \\begin{cases} 2 &amp;&amp; |\\omega | \\leq 2 \\\\ 0 &amp;&amp; | \\omega | \\geq 2 \\end{cases}<\/span>\n\n\n\n<p>la funci\u00f3n de transferencia del sistema.<\/p>\n\n\n\n<p>Calcular:<\/p>\n\n\n\n<p>a) La P[<strong>X<\/strong>(t+1)-<strong>X<\/strong>(t)&gt;1]<\/p>\n\n\n\n<p>b) La potencia media de <strong>X<\/strong>(t) y de <strong>Y<\/strong>(t)<\/p>\n\n\n\n<p>c) La P[<strong>Y<\/strong>(t)&lt;1]<\/p>\n\n\n\n<p><strong>R\u00fabrica<\/strong>: literal a y c (6 puntos), literal b (8 puntos)<\/p>\n","protected":false},"excerpt":{"rendered":"<p>3ra Evaluaci\u00f3n III T\u00e9rmino 2012-2013. Abril 19, 2013. FIEC03236 Tema 6 (20 puntos). Sea X(t) un proceso normal y estacionario, con media 0 y densidad espectral: Y sea Y(t) la respuesta de un sistema lineal a la entrada X(t), siendo: la funci\u00f3n de transferencia del sistema. Calcular: a) La P[X(t+1)-X(t)&gt;1] b) La potencia media de [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-stp-ejercicios","format":"standard","meta":{"footnotes":""},"categories":[212],"tags":[],"class_list":["post-1047","post","type-post","status-publish","format-standard","hentry","category-stp-3eva"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/1047","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=1047"}],"version-history":[{"count":4,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/1047\/revisions"}],"predecessor-version":[{"id":23520,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/1047\/revisions\/23520"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=1047"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=1047"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=1047"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}