{"id":10698,"date":"2014-03-04T11:00:56","date_gmt":"2014-03-04T16:00:56","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/ccpg1001\/?p=10698"},"modified":"2026-04-05T17:53:26","modified_gmt":"2026-04-05T22:53:26","slug":"s2eva2004tii_t1-calcular-raiz-cubica-recursiva","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/fp-s2eva10\/s2eva2004tii_t1-calcular-raiz-cubica-recursiva\/","title":{"rendered":"s2Eva2004TII_T1 Calcular ra\u00edz c\u00fabica recursiva"},"content":{"rendered":"\n<p><em><strong>Ejercicio<\/strong><\/em>: <a href=\"https:\/\/blog.espol.edu.ec\/algoritmos101\/fp-2eva10\/2eva2004tii_t1-calcular-raiz-cubica-recursiva\/\" data-type=\"post\" data-id=\"2877\">2Eva2004TII_T1 Calcular ra\u00edz c\u00fabica recursiva<\/a><\/p>\n\n\n\n<p>Usar la f\u00f3rmula recursiva:<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> x = \\frac{2 x^3+n}{3 x^2}<\/span>\n\n\n\n<p>considere controlar el n\u00famero de iteraciones como m\u00e1ximo 100 veces (tarea). Para evitar un bucle infinito si la diferencia no disminuye (convergente).<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">Algoritmo en Python<\/h2>\n\n\n<div class=\"wp-block-syntaxhighlighter-code \"><pre class=\"brush: python; title: ; notranslate\" title=\"\">\n# 2Eva_IIT2004_T1 Calcular ra\u00edz c\u00fabica recursiva\n\ndef cubic(n, tolera = 0.0001):\n    xi = 1\n    diferencia = 1\n    while (diferencia&gt;tolera):\n        xn = (2*(xi**3)+n)\/(3*(xi**2))\n        diferencia = abs(xn-xi)\n        xi = xn\n    return(xi)\n<\/pre><\/div>\n\n\n<p>resultado del algoritmo<\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>&gt;&gt;&gt; cubic(8)\n2.0000000000120624\n&gt;&gt;&gt; cubic(27)\n3.0000000000000973\n&gt;&gt;&gt; <\/code><\/pre>\n","protected":false},"excerpt":{"rendered":"<p>Ejercicio: 2Eva2004TII_T1 Calcular ra\u00edz c\u00fabica recursiva Usar la f\u00f3rmula recursiva: considere controlar el n\u00famero de iteraciones como m\u00e1ximo 100 veces (tarea). Para evitar un bucle infinito si la diferencia no disminuye (convergente). Algoritmo en Python resultado del algoritmo<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-fp-ejemplos","format":"standard","meta":{"footnotes":""},"categories":[131],"tags":[58,157],"class_list":["post-10698","post","type-post","status-publish","format-standard","hentry","category-fp-s2eva10","tag-ejemplos-python","tag-fundamentos-programacion"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/10698","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=10698"}],"version-history":[{"count":5,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/10698\/revisions"}],"predecessor-version":[{"id":23661,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/10698\/revisions\/23661"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=10698"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=10698"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=10698"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}