{"id":1103,"date":"2018-02-23T01:46:34","date_gmt":"2018-02-23T06:46:34","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1013\/?p=1103"},"modified":"2025-12-13T09:33:58","modified_gmt":"2025-12-13T14:33:58","slug":"3eva2017tii_t3-edp-eliptica-placa-rectangular","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/mn-3eva20\/3eva2017tii_t3-edp-eliptica-placa-rectangular\/","title":{"rendered":"3Eva2017TII_T3 EDP El\u00edptica, placa rectangular"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">3ra Evaluaci\u00f3n II T\u00e9rmino 2017-2018. Febrero 20, 2018. MATG1013<\/h2>\n\n\n\n<p><strong>Tema 3<\/strong>. Aproxime la soluci\u00f3n de la siguiente EDP el\u00edptica.<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> \\frac{\\partial^2 u}{\\partial x^2} + \\frac{\\partial ^2u}{\\partial y^2} = (x^2 + y^2) e^{xy}<\/span>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> 0 \\lt x \\lt 2, 0 \\lt y \\lt 1 <\/span>\n\n\n\n<p>con condiciones de frontera<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> u(0,y) = 1 , u(2,y) = e^{2y}, 0 \\leq y \\leq 1 <\/span>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> u(x,0) = 1, u(x,1) = e^x , 0 \\leq x \\leq 2 <\/span>\n\n\n\n<p>a) use tama\u00f1os de paso h = 2\/3 y k = 1\/3<\/p>\n\n\n\n<p>b) compare con la soluci\u00f3n u(x,y) = e<sup>xy<\/sup> en forma gr\u00e1fica<\/p>\n","protected":false},"excerpt":{"rendered":"<p>3ra Evaluaci\u00f3n II T\u00e9rmino 2017-2018. Febrero 20, 2018. MATG1013 Tema 3. Aproxime la soluci\u00f3n de la siguiente EDP el\u00edptica. con condiciones de frontera a) use tama\u00f1os de paso h = 2\/3 y k = 1\/3 b) compare con la soluci\u00f3n u(x,y) = exy en forma gr\u00e1fica<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-mn","format":"standard","meta":{"footnotes":""},"categories":[28],"tags":[57],"class_list":["post-1103","post","type-post","status-publish","format-standard","hentry","category-mn-3eva20","tag-edp"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/1103","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=1103"}],"version-history":[{"count":2,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/1103\/revisions"}],"predecessor-version":[{"id":17675,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/1103\/revisions\/17675"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=1103"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=1103"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=1103"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}