{"id":1128,"date":"2016-11-30T19:18:47","date_gmt":"2016-12-01T00:18:47","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/estg1003\/?p=1128"},"modified":"2026-04-18T15:17:49","modified_gmt":"2026-04-18T20:17:49","slug":"distribucion-normal-estandar-acumulada-tabla","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/stp-recursos\/distribucion-normal-estandar-acumulada-tabla\/","title":{"rendered":"Distribuci\u00f3n Normal est\u00e1ndar acumulada - Tabla"},"content":{"rendered":"\n

Referencia<\/strong>: Gubner 5.1 Table 5.1 p 189 <\/em><\/p>\n\n\n\n

Valores de la funci\u00f3n de distribuci\u00f3n acumulada normal est\u00e1ndar \u03a6(x) y su complementaria Q(x)= 1- \u03a6(x). Para evaluar \u03a6 y Q para argumentos negativos, use el hecho que la densidad normal est\u00e1ndar es par, \u03a6(-x) = Q(x).<\/p>\n\n\n \\Phi(x)= \\frac{1}{\\sqrt{2 \\pi}} \\int_{-\\infty}^{x} e^{-t^2 \/2} dt<\/span>\n\n\n Q(x) = 1- \\Phi(x) = \\frac{1}{\\sqrt{2 \\pi}} \\int_{x}^{\\infty} e^{-t^2 \/2} dt<\/span>\n\n\n\n

\n
\n
x<\/strong><\/th>\u03a6(x)<\/th>Q(x)<\/th><\/tr>
0.0<\/td>0.5000<\/td>0.5000<\/td><\/tr>
0.1<\/td>0.5398<\/td>0.4602<\/td><\/tr>
0.2<\/td>0.5793<\/td>0.4207<\/td><\/tr>
0.3<\/td>0.6179<\/td>0.3821<\/td><\/tr>
0.4<\/td>0.6554<\/td>0.3446<\/td><\/tr>
0.5<\/td>0.6915<\/td>0.3085<\/td><\/tr>
0.6<\/td>0.7257<\/td>0.2743<\/td><\/tr>
0.7<\/td>0.7580<\/td>0.2420<\/td><\/tr>
0.8<\/td>0.7881<\/td>0.2119<\/td><\/tr>
0.9<\/td>0.8159<\/td>0.1841<\/td><\/tr>
1.0<\/td>0.8413<\/td>0.1587<\/td><\/tr>
1.1<\/td>0.8643<\/td>0.1357<\/td><\/tr>
1.2<\/td>0.8849<\/td>0.1151<\/td><\/tr>
1.3<\/td>0.9032<\/td>0.0968<\/td><\/tr>
1.4<\/td>0.9192<\/td>0.0808<\/td><\/tr>
1.5<\/td>0.9332<\/td>0.0668<\/td><\/tr>
1.6<\/td>0.9452<\/td>0.0548<\/td><\/tr>
1.7<\/td>0.9554<\/td>0.0446<\/td><\/tr>
1.8<\/td>0.9641<\/td>0.0359<\/td><\/tr>
1.9<\/td>0.9713<\/td>0.0287<\/td><\/tr><\/tbody><\/table><\/figure>\n<\/div>\n\n\n\n
\n
x<\/th>\u03a6(x)<\/th>Q(x)<\/th><\/tr>
2.0<\/td>0.9772<\/td>0.0228<\/td><\/tr>
2.1<\/td>0.9821<\/td>0.0179<\/td><\/tr>
2.2<\/td>0.9861<\/td>0.0139<\/td><\/tr>
2.3<\/td>0.9893<\/td>0.0107<\/td><\/tr>
2.4<\/td>0.9918<\/td>0.0082<\/td><\/tr>
2.5<\/td>0.9938<\/td>0.0062<\/td><\/tr>
2.6<\/td>0.9953<\/td>0.0047<\/td><\/tr>
2.7<\/td>0.9965<\/td>0.0035<\/td><\/tr>
2.8<\/td>0.9974<\/td>0.0026<\/td><\/tr>
2.9<\/td>0.9981<\/td>0.0019<\/td><\/tr>
3.0<\/td>0.9987<\/td>0.0013<\/td><\/tr>
3.1<\/td>0.9990<\/td>0.0010<\/td><\/tr>
3.2<\/td>0.9993<\/td>0.0007<\/td><\/tr>
3.3<\/td>0.9995<\/td>0.0005<\/td><\/tr>
3.4<\/td>0.9997<\/td>0.0003<\/td><\/tr>
3.5<\/td>0.9998<\/td>0.0002<\/td><\/tr>
3.6<\/td>0.9998<\/td>0.0002<\/td><\/tr>
3.7<\/td>0.9999<\/td>0.0001<\/td><\/tr>
3.8<\/td>0.9999<\/td>0.0001<\/td><\/tr>
3.9<\/td>1.0000<\/td>0.0000<\/td><\/tr><\/tbody><\/table><\/figure>\n<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

Referencia: Gubner 5.1 Table 5.1 p 189 Valores de la funci\u00f3n de distribuci\u00f3n acumulada normal est\u00e1ndar \u03a6(x) y su complementaria Q(x)= 1- \u03a6(x). Para evaluar \u03a6 y Q para argumentos negativos, use el hecho que la densidad normal est\u00e1ndar es par, \u03a6(-x) = Q(x). x \u03a6(x) Q(x) 0.0 0.5000 0.5000 0.1 0.5398 0.4602 0.2 0.5793 […]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-stp-unidades","format":"standard","meta":{"footnotes":""},"categories":[205],"tags":[],"class_list":["post-1128","post","type-post","status-publish","format-standard","hentry","category-stp-recursos"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/1128","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=1128"}],"version-history":[{"count":4,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/1128\/revisions"}],"predecessor-version":[{"id":24370,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/1128\/revisions\/24370"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=1128"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=1128"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=1128"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}