{"id":1702,"date":"2017-10-22T17:20:33","date_gmt":"2017-10-22T22:20:33","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/telg1001\/?p=1702"},"modified":"2026-04-04T10:19:20","modified_gmt":"2026-04-04T15:19:20","slug":"1eva2012ti_t2-lti-dt-en-serie","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/ss-1eva\/1eva2012ti_t2-lti-dt-en-serie\/","title":{"rendered":"1Eva2012TI_T2 LTI DT en serie"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">1ra Evaluaci\u00f3n I T\u00e9rmino 2012-2013. 5\/julio\/2012. TELG1001<\/h2>\n\n\n\n<p><strong>Tema 2<\/strong>. (30 puntos) Dos sistemas LTI-DT tienen respuesta impulso h<sub>1<\/sub>[n] y h<sub>2<\/sub>[n] respectivamente. Los sistemas en referencia, utilizados como subsistemas, son conectados en cascada con la finalidad de conformar un sistema total, tal como se muestra en la siguiente figura.<\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"504\" height=\"90\" src=\"http:\/\/blog.espol.edu.ec\/algoritmos101\/files\/2017\/09\/1E2010TI_T3_LTID_Diagrama2.png\" alt=\"1E2010TI_T3 LTID Diagrama 2\" class=\"wp-image-20082\" \/><\/figure>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> h_1 [n] = (0.8)^n \\mu [n] - 0.3 (0.8)^{n-1} \\mu [n-1]<\/span>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> h_2 [n] = (0.3)^n \\mu [n] - 0.8 (0.3)^{n-1} \\mu [n-1]<\/span>\n\n\n\n<p>a. Determinar la respuesta impulso del sistema total e indicar a qu\u00e9 tipo de sistema pertenece (FIR o IIR).<\/p>\n\n\n\n<p>b. Justificando su respuesta, indique si el sistema es BIBO estable o no.<\/p>\n\n\n\n<p>c. Determinar y esquematizar la respuesta de dicho sistema, conociendo que:<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> x[n] = \\delta [n] - \\delta [n-1]<\/span>\n","protected":false},"excerpt":{"rendered":"<p>1ra Evaluaci\u00f3n I T\u00e9rmino 2012-2013. 5\/julio\/2012. TELG1001 Tema 2. (30 puntos) Dos sistemas LTI-DT tienen respuesta impulso h1[n] y h2[n] respectivamente. Los sistemas en referencia, utilizados como subsistemas, son conectados en cascada con la finalidad de conformar un sistema total, tal como se muestra en la siguiente figura. a. Determinar la respuesta impulso del sistema [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-ss-ejercicios","format":"standard","meta":{"footnotes":""},"categories":[178],"tags":[182,183],"class_list":["post-1702","post","type-post","status-publish","format-standard","hentry","category-ss-1eva","tag-lti-dt","tag-transformada-z"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/1702","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=1702"}],"version-history":[{"count":2,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/1702\/revisions"}],"predecessor-version":[{"id":20121,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/1702\/revisions\/20121"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=1702"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=1702"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=1702"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}