{"id":1778,"date":"2018-02-02T10:01:34","date_gmt":"2018-02-02T15:01:34","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/telg1001\/?p=1778"},"modified":"2025-12-28T17:36:49","modified_gmt":"2025-12-28T22:36:49","slug":"3eva2009tii_t2-lti-dt-hz-con-subsistemas-de-bloques-en-serie","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/ss-3eva\/3eva2009tii_t2-lti-dt-hz-con-subsistemas-de-bloques-en-serie\/","title":{"rendered":"3Eva2009TII_T2 LTI DT H(z) con subsistemas de bloques en serie"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">3ra Evaluaci\u00f3n II T\u00e9rmino 2009-2010. 18\/Febrero\/2010. TELG1001<\/h2>\n\n\n\n<p><strong>Tema 2<\/strong>. (20 puntos) El sistema que se muestra en la siguiente figura, es el resultante de la combinaci\u00f3n de dos subsistemas conectados en cascada. <\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"947\" height=\"191\" src=\"http:\/\/blog.espol.edu.ec\/algoritmos101\/files\/2018\/02\/3E2009TII_T2_LTID_diagrama1.png\" alt=\"3E2009TII_T2 LTI D diagrama 1\" class=\"wp-image-20267\" \/><\/figure>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"480\" height=\"130\" src=\"http:\/\/blog.espol.edu.ec\/algoritmos101\/files\/2017\/10\/1E2014TI_T2_LTID_Diagrama1.png\" alt=\"1E2014TI_T2 LTI D Diagrama 1\" class=\"wp-image-20151\" \/><\/figure>\n\n\n\n<p>Determinar:<\/p>\n\n\n\n<p>a. Las respuestas impulso de cada subsistema y del sistema completo. Es decir h<sub>1<\/sub>[n], h<sub>2<\/sub>[n], h[n].<\/p>\n\n\n\n<p>b. Su respuesta y[n], en la forma de m\u00ednima expresi\u00f3n, frente a la siguiente entrada:<\/p>\n\n\n\n<p class=\"has-text-align-center\">x[n] = \u03b4[n] - 2 \u03b4[n-1]<\/p>\n","protected":false},"excerpt":{"rendered":"<p>3ra Evaluaci\u00f3n II T\u00e9rmino 2009-2010. 18\/Febrero\/2010. TELG1001 Tema 2. (20 puntos) El sistema que se muestra en la siguiente figura, es el resultante de la combinaci\u00f3n de dos subsistemas conectados en cascada. Determinar: a. Las respuestas impulso de cada subsistema y del sistema completo. Es decir h1[n], h2[n], h[n]. b. Su respuesta y[n], en la [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-ss-ejercicios","format":"standard","meta":{"footnotes":""},"categories":[188],"tags":[179,182,183],"class_list":["post-1778","post","type-post","status-publish","format-standard","hentry","category-ss-3eva","tag-diagrama-de-bloques","tag-lti-dt","tag-transformada-z"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/1778","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=1778"}],"version-history":[{"count":3,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/1778\/revisions"}],"predecessor-version":[{"id":20269,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/1778\/revisions\/20269"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=1778"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=1778"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=1778"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}