{"id":17829,"date":"2018-03-08T19:32:21","date_gmt":"2018-03-09T00:32:21","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/telg1001\/?p=1959"},"modified":"2025-12-28T18:20:20","modified_gmt":"2025-12-28T23:20:20","slug":"3eva2012ti_t1-lti-dt-encontrar-h1n-dado-yn-y-h2n-bloques-en-serie","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/ss-3eva\/3eva2012ti_t1-lti-dt-encontrar-h1n-dado-yn-y-h2n-bloques-en-serie\/","title":{"rendered":"3Eva2012TI_T1 LTI DT encontrar h1[n] dado y[n] y h2[n], bloques en serie"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">3ra Evaluaci\u00f3n I T\u00e9rmino 2012-2013. 13\/Septiembre\/2012. TELG1001<\/h2>\n\n\n\n<p><strong>Tema 1<\/strong>. (25 puntos) Asumiendo causalidad para los sistemas en serie h<sub>1<\/sub>[n] y h<sub>2<\/sub>[n], se le solicita que mediante la utilizaci\u00f3n de la transformada z, determine la respuesta impulso h<sub>1<\/sub>[n], si se conoce y[n]:<\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"480\" height=\"130\" src=\"http:\/\/blog.espol.edu.ec\/algoritmos101\/files\/2017\/10\/1E2014TI_T2_LTID_Diagrama1.png\" alt=\"1E2014TI_T2 LTI D Diagrama 1\" class=\"wp-image-20151\" \/><\/figure>\n\n\n\n<figure class=\"wp-block-image alignright size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"292\" height=\"239\" src=\"http:\/\/blog.espol.edu.ec\/algoritmos101\/files\/2018\/03\/3E2012TI_T1_LTID_diagrama2.png\" alt=\"3E2012TI_T1 LTI D diagrama 2\" class=\"wp-image-20333\" \/><\/figure>\n\n\n\n<p>a. La respuesta del segundo sistema est\u00e1 dada por:<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> h_2 [n] = \\delta[n] - \\delta[n-1] <\/span>\n\n\n\n<p>b. Si dada la entrada x[n] se obtiene una salida y[n] esquematizada por:<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> x [n] = \\mu [n] - \\mu [n-2] <\/span>\n","protected":false},"excerpt":{"rendered":"<p>3ra Evaluaci\u00f3n I T\u00e9rmino 2012-2013. 13\/Septiembre\/2012. TELG1001 Tema 1. (25 puntos) Asumiendo causalidad para los sistemas en serie h1[n] y h2[n], se le solicita que mediante la utilizaci\u00f3n de la transformada z, determine la respuesta impulso h1[n], si se conoce y[n]: a. La respuesta del segundo sistema est\u00e1 dada por: b. Si dada la entrada [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-ss-ejercicios","format":"standard","meta":{"footnotes":""},"categories":[188],"tags":[182,183],"class_list":["post-17829","post","type-post","status-publish","format-standard","hentry","category-ss-3eva","tag-lti-dt","tag-transformada-z"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/17829","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=17829"}],"version-history":[{"count":3,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/17829\/revisions"}],"predecessor-version":[{"id":20334,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/17829\/revisions\/20334"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=17829"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=17829"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=17829"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}