{"id":1793,"date":"2017-12-10T12:05:09","date_gmt":"2017-12-10T17:05:09","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/telg1001\/?p=1793"},"modified":"2025-12-28T10:39:22","modified_gmt":"2025-12-28T15:39:22","slug":"2eva2010ti_t2-lti-ct-salida-a-xt","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/ss-2eva\/2eva2010ti_t2-lti-ct-salida-a-xt\/","title":{"rendered":"2Eva2010TI_T2 LTI CT salida a x(t)"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">2da Evaluaci\u00f3n I T\u00e9rmino 2010-2011. 2\/Septiembre\/2010. TELG1001<\/h2>\n\n\n\n<p><strong>Tema 2<\/strong>. (20 puntos) Considere el sistema mostrado en la siguiente figura:<\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"449\" height=\"108\" src=\"http:\/\/blog.espol.edu.ec\/algoritmos101\/files\/2017\/12\/2E2010TI_T2_LTIC_diagrama1.png\" alt=\"2E2010TI_T2 LTIC diagrama 1\" class=\"wp-image-20200\" \/><\/figure>\n\n\n\n<p>Donde<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> w(t) = \\cos(5 \\pi t) <\/span>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> h(t) = \\frac{\\sin (6 \\pi t)}{\\pi t} <\/span>\n\n\n\n<p>y la respuesta de frecuencia de X(\u03c9) esta dada por:<\/p>\n\n\n\n<figure class=\"wp-block-image alignright size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"429\" height=\"205\" src=\"http:\/\/blog.espol.edu.ec\/algoritmos101\/files\/2017\/12\/2E2010TI_T2_LTIC_diagrama2.png\" alt=\"2E2010TI_T2 LTI C diagrama 2\" class=\"wp-image-20202\" \/><\/figure>\n\n\n\n<p>Encontrar, esquematizar y etiquetar, seg\u00fan corresponda:<\/p>\n\n\n\n<p>a. La transformada de Fourier de la se\u00f1al g(t). Es decir G(\u03c9).<\/p>\n\n\n\n<p>b. La transformada de Fourier de la se\u00f1al c(t). Es decir C(\u03c9).<\/p>\n\n\n\n<p>c. La transformada de Fourier de la se\u00f1al y(t). Es decir Y(\u03c9).<\/p>\n","protected":false},"excerpt":{"rendered":"<p>2da Evaluaci\u00f3n I T\u00e9rmino 2010-2011. 2\/Septiembre\/2010. TELG1001 Tema 2. (20 puntos) Considere el sistema mostrado en la siguiente figura: Donde y la respuesta de frecuencia de X(\u03c9) esta dada por: Encontrar, esquematizar y etiquetar, seg\u00fan corresponda: a. La transformada de Fourier de la se\u00f1al g(t). Es decir G(\u03c9). b. La transformada de Fourier de la [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-ss-ejercicios","format":"standard","meta":{"footnotes":""},"categories":[186],"tags":[180,185],"class_list":["post-1793","post","type-post","status-publish","format-standard","hentry","category-ss-2eva","tag-lti-ct","tag-transformada-fourier"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/1793","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=1793"}],"version-history":[{"count":3,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/1793\/revisions"}],"predecessor-version":[{"id":20203,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/1793\/revisions\/20203"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=1793"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=1793"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=1793"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}