{"id":22036,"date":"2016-08-18T07:36:54","date_gmt":"2016-08-18T12:36:54","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/estg1003\/?p=515"},"modified":"2026-04-05T16:13:50","modified_gmt":"2026-04-05T21:13:50","slug":"1eva2009tii_t4-fiec-funcion-densidad-conjunta","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/stp-1eva\/1eva2009tii_t4-fiec-funcion-densidad-conjunta\/","title":{"rendered":"1Eva2009TII_T4 FIEC Funci\u00f3n densidad conjunta"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">1ra Evaluaci\u00f3n II T\u00e9rmino 2009-2010. Diciembre 3, 2009 . FIEC03236<\/h2>\n\n\n\n<p><strong>Funci\u00f3n densidad de probabilidad conjunta<\/strong><\/p>\n\n\n\n<p><strong>Tema 4.&nbsp;<\/strong>&nbsp;Para las variables aleatorias <strong>X<\/strong>,<strong>Y<\/strong> con la funci\u00f3n densidad conjunta mostrada, calcule los literales:<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> f_{XY}(x,y) = \\begin{cases} k(x+y) &amp; 0\\leq y\\leq x\\leq3 \\\\ 0 &amp; \\text{otro caso}\\end{cases} <\/span>\n\n\n\n<p>a) \u00a0 el valor de <strong>k<\/strong> , que justifica la funci\u00f3n<\/p>\n\n\n\n<p>b) \u00a0 funci\u00f3n densidad de probabilidad para <strong>Y<\/strong>: f<sub>Y<\/sub>(y)<\/p>\n\n\n\n<p>c)\u00a0\u00a0 El valor esperado E[Y|x]<\/p>\n\n\n\n<p>d)\u00a0\u00a0 Calcule P(0&lt;X+Y&lt;2)<\/p>\n\n\n\n<p><strong>Nota<\/strong>: Dibuje con detalle el \u00e1rea de integraci\u00f3n, escriba con claridad los l\u00edmites de integraci\u00f3n, y los rangos de validez donde sea necesario.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>1ra Evaluaci\u00f3n II T\u00e9rmino 2009-2010. Diciembre 3, 2009 . FIEC03236 Funci\u00f3n densidad de probabilidad conjunta Tema 4.&nbsp;&nbsp;Para las variables aleatorias X,Y con la funci\u00f3n densidad conjunta mostrada, calcule los literales: a) \u00a0 el valor de k , que justifica la funci\u00f3n b) \u00a0 funci\u00f3n densidad de probabilidad para Y: fY(y) c)\u00a0\u00a0 El valor esperado E[Y|x] [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-stp-ejercicios","format":"standard","meta":{"footnotes":""},"categories":[208],"tags":[217],"class_list":["post-22036","post","type-post","status-publish","format-standard","hentry","category-stp-1eva","tag-bivariada-continua"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/22036","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=22036"}],"version-history":[{"count":4,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/22036\/revisions"}],"predecessor-version":[{"id":23497,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/22036\/revisions\/23497"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=22036"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=22036"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=22036"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}