{"id":2298,"date":"2018-01-17T08:15:38","date_gmt":"2018-01-17T13:15:38","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/telg1001\/?p=2298"},"modified":"2025-12-28T08:49:30","modified_gmt":"2025-12-28T13:49:30","slug":"s2eva2016tii_t4-resolver-dominio-frecuencia","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/ss-ejemplos\/ss-s2eva\/s2eva2016tii_t4-resolver-dominio-frecuencia\/","title":{"rendered":"s2Eva2016TII_T4 resolver en dominio de frecuencia"},"content":{"rendered":"\n<p><em><strong>Ejercicio<\/strong><\/em>: <a href=\"https:\/\/blog.espol.edu.ec\/algoritmos101\/ss-evalua\/ss-2eva\/2eva2016tii_t4-resolver-dominio-frecuencia\/\" data-type=\"post\" data-id=\"17826\">2Eva2016TII_T4 resolver en dominio de frecuencia<\/a><\/p>\n\n\n\n<p>Partiendo de,<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> y(t) = x(t) \\circledast h(t) <\/span>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> Y(\\omega) = X(\\omega) H(\\omega) <\/span>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> Y\\Big(\\frac{\\omega}{3}\\Big) = X\\Big(\\frac{\\omega}{3}\\Big) H\\Big(\\frac{\\omega}{3}\\Big) <\/span>\n\n\n\n<p>se tiene tambi\u00e9n que:<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> g(t) = x(3t) \\circledast h(3t) <\/span>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> G(\\omega) = \\frac{1}{3}X\\Big(\\frac{\\omega}{3}\\Big)\\text{ } \\frac{1}{3}H\\Big(\\frac{\\omega}{3}\\Big)<\/span>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> = \\frac{1}{9}X\\Big(\\frac{\\omega}{3}\\Big)H\\Big(\\frac{\\omega}{3}\\Big) = \\frac{1}{9}Y\\Big(\\frac{\\omega}{3}\\Big)<\/span>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> G(\\omega) = \\frac{1}{3} \\Bigg[\\frac{1}{3}Y\\Big(\\frac{\\omega}{3}\\Big)\\Bigg]<\/span>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> g(t) = \\frac{1}{3} y(3t)<\/span>\n\n\n\n<p class=\"has-text-align-center\">A = 1\/3<br>B = 3<\/p>\n\n\n\n<p>&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Ejercicio: 2Eva2016TII_T4 resolver en dominio de frecuencia Partiendo de, se tiene tambi\u00e9n que: A = 1\/3B = 3 &nbsp;<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-ss-ejercicios","format":"standard","meta":{"footnotes":""},"categories":[187],"tags":[199],"class_list":["post-2298","post","type-post","status-publish","format-standard","hentry","category-ss-s2eva","tag-senalessistemas"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/2298","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=2298"}],"version-history":[{"count":3,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/2298\/revisions"}],"predecessor-version":[{"id":19760,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/2298\/revisions\/19760"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=2298"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=2298"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=2298"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}