{"id":248,"date":"2017-11-16T13:30:33","date_gmt":"2017-11-16T18:30:33","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1013\/?p=248"},"modified":"2026-04-05T05:44:00","modified_gmt":"2026-04-05T10:44:00","slug":"1eva2016ti_t1_mn-contaminante-en-lago","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/mn-1eva20\/1eva2016ti_t1_mn-contaminante-en-lago\/","title":{"rendered":"1Eva2016TI_T1_MN Contaminante en lago"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">1ra Evaluaci\u00f3n I T\u00e9rmino 2016-2017. 28\/junio\/2016. ICM02188 M\u00e9todos Num\u00e9ricos<\/h2>\n\n\n\n<p><strong>Tema 1<\/strong>. (25 puntos) El balance de masa de un contaminante en un lago, bien mezclado, se expresa mediante la ecuaci\u00f3n:<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> V\\frac{dc}{dt} = W - Qc-kV(\\sqrt[3]{c})<\/span>\n\n\n\n<p>Dados los valores de par\u00e1metros:<\/p>\n\n\n\n<p>V=1x10<sup>6<\/sup> m<sup>3<\/sup>,<\/p>\n\n\n\n<p>Q=1x10<sup>5<\/sup> m<sup>3<\/sup>\/a\u00f1o<\/p>\n\n\n\n<p>W=1x10<sup>6<\/sup> g\/a\u00f1o<\/p>\n\n\n\n<p>k=0.25m<sup>0.5<\/sup>\/g<sup>0.5<\/sup>\/a\u00f1o<\/p>\n\n\n\n<p>se quiere hallar la concentraci\u00f3n c de estado estable (dc\/dt= 0)<\/p>\n\n\n\n<p>a) Utilizando el m\u00e9todo de Newton, encuentre un modelo iterativo <strong>x<\/strong>=<strong>g<\/strong>(<strong>x<\/strong>) para aproximar <em><strong>c<\/strong><\/em> y un intervalo de existencia y convergencia.<\/p>\n\n\n\n<p>b) Realice las iteraciones presentando el error en cada iteraci\u00f3n.<\/p>\n\n\n\n<p><strong><em>R\u00fabrica<\/em><\/strong>:<br>a) Hallar <strong>g<\/strong> (5 puntos), intervalo de existencia (2 puntos), intervalo de convergencia (6 puntos)<br>b) Iteraciones hasta (8 puntos), estimaci\u00f3n del error hasta (4 puntos)<\/p>\n","protected":false},"excerpt":{"rendered":"<p>1ra Evaluaci\u00f3n I T\u00e9rmino 2016-2017. 28\/junio\/2016. ICM02188 M\u00e9todos Num\u00e9ricos Tema 1. (25 puntos) El balance de masa de un contaminante en un lago, bien mezclado, se expresa mediante la ecuaci\u00f3n: Dados los valores de par\u00e1metros: V=1x106 m3, Q=1x105 m3\/a\u00f1o W=1x106 g\/a\u00f1o k=0.25m0.5\/g0.5\/a\u00f1o se quiere hallar la concentraci\u00f3n c de estado estable (dc\/dt= 0) a) Utilizando [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-mn","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[66],"class_list":["post-248","post","type-post","status-publish","format-standard","hentry","category-mn-1eva20","tag-raices"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/248","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=248"}],"version-history":[{"count":4,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/248\/revisions"}],"predecessor-version":[{"id":14110,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/248\/revisions\/14110"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=248"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=248"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=248"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}