{"id":2617,"date":"2014-11-10T16:30:58","date_gmt":"2014-11-10T21:30:58","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/icm00794\/?p=2617"},"modified":"2026-09-24T20:01:41","modified_gmt":"2026-09-25T01:01:41","slug":"3eva2011ti_t2-producto-de-matrices","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/fp-3eva20\/3eva2011ti_t2-producto-de-matrices\/","title":{"rendered":"3Eva2011TI_T2 producto de matrices"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\" id=\"3EvaIT2011\">3ra Evaluaci\u00f3n I T\u00e9rmino 2011-2012, Septiembre 13, 2011 \/ICM00794<\/h2>\n\n\n\n<p><strong>Tema 2<\/strong> (15 puntos). Dos matrices <strong>A<\/strong> y <strong>B<\/strong> se pueden multiplicar si el n\u00famero de columnas de <strong>A<\/strong> coincide con el n\u00famero de filas de <strong>B<\/strong>.<\/p>\n\n\n\n<p class=\"has-text-align-center\"><strong>A<\/strong><sub>m x n<\/sub> x <strong>B<\/strong><sub>n x p<\/sub> = <strong>C<\/strong><sub>m x p<\/sub><\/p>\n\n\n\n<p>El elemento <strong>C<\/strong><sub>ij<\/sub> de la matriz producto se obtiene multiplicando cada elemento de la fila <strong>i<\/strong> de la matriz <strong>A<\/strong> por cada elemento de la columna <strong>j<\/strong> de la matriz <strong>B<\/strong> y sum\u00e1ndolos.<\/p>\n\n\n\n<p>Realice una funci\u00f3n <strong>producto<\/strong>(<strong>A<\/strong>,<strong>B<\/strong>) que permita realizar el producto entre una matriz <strong>A<\/strong> de tama\u00f1o de <strong>m<\/strong>x<strong>n<\/strong> y un vector <strong>B<\/strong> de tama\u00f1o <strong>n<\/strong>.<\/p>\n\n\n\n<p><strong>A<\/strong> x <strong>B<\/strong> =  <strong>C<\/strong><\/p>\n\n\n\n<div class=\"wp-block-group alignwide is-content-justification-center is-nowrap is-layout-flex wp-container-core-group-is-layout-23441af8 wp-block-group-is-layout-flex\">\n<figure class=\"wp-block-table\"><table><tbody><tr><td><mark style=\"background-color:#FFEE58\" class=\"has-inline-color\">2<\/mark><\/td><td>1<\/td><td>2<\/td><td>3<\/td><\/tr><tr><td>3<\/td><td>1<\/td><td>0<\/td><td>2<\/td><\/tr><tr><td>2<\/td><td>2<\/td><td>1<\/td><td>1<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<p class=\"has-text-align-center\"><strong>x<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-table\"><table><tbody><tr><td><mark style=\"background-color:#FFEE58\" class=\"has-inline-color\">25<\/mark><\/td><\/tr><tr><td>50<\/td><\/tr><tr><td>100<\/td><\/tr><tr><td>150<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<p>=<\/p>\n\n\n\n<figure class=\"wp-block-table\"><table><tbody><tr><td><mark style=\"background-color:#FFEE58\" class=\"has-inline-color\">2<\/mark>*<mark style=\"background-color:#FFEE58\" class=\"has-inline-color\">25<\/mark>=<strong><mark style=\"background-color:#FFEE58\" class=\"has-inline-color\">50<\/mark><\/strong><\/td><td>1*50=<strong>50<\/strong><\/td><td>2*100=<strong>200<\/strong><\/td><td>3*150=<strong>450 <\/strong><\/td><\/tr><tr><td>75<\/td><td>50<\/td><td>0<\/td><td>300<\/td><\/tr><tr><td>50<\/td><td>100<\/td><td>100<\/td><td>150<\/td><\/tr><\/tbody><\/table><\/figure>\n<\/div>\n\n\n\n<p><strong>Nota<\/strong>: Desarrolle el algoritmo que describa las operaciones para cada elemento C<sub>ij<\/sub>. No use las funciones de matlab o Python para multiplicar matrices.<\/p>\n\n\n\n<p><strong> R\u00fabrica<\/strong>: Primera fila(5 puntos), todas las filas 5 puntos, funci\u00f3n (5 puntos),<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\" \/>\n\n\n\n<pre class=\"wp-block-code\"><code>A = &#091;&#091;2,1,2,3],\n     &#091;3,1,0,2],\n     &#091;2,2,1,1]]\nB = &#091;25,50,100,150]<\/code><\/pre>\n","protected":false},"excerpt":{"rendered":"<p>3ra Evaluaci\u00f3n I T\u00e9rmino 2011-2012, Septiembre 13, 2011 \/ICM00794 Tema 2 (15 puntos). Dos matrices A y B se pueden multiplicar si el n\u00famero de columnas de A coincide con el n\u00famero de filas de B. Am x n x Bn x p = Cm x p El elemento Cij de la matriz producto se [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-fp-ejercicios","format":"standard","meta":{"footnotes":""},"categories":[122],"tags":[148,155],"class_list":["post-2617","post","type-post","status-publish","format-standard","hentry","category-fp-3eva20","tag-arreglos-matrices","tag-funciones"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/2617","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=2617"}],"version-history":[{"count":8,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/2617\/revisions"}],"predecessor-version":[{"id":26027,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/2617\/revisions\/26027"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=2617"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=2617"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=2617"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}