{"id":278,"date":"2017-11-15T13:15:32","date_gmt":"2017-11-15T18:15:32","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1013\/?p=278"},"modified":"2025-12-04T08:53:28","modified_gmt":"2025-12-04T13:53:28","slug":"1eva2015ti_t4-lingotes-metales","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/mn-1eva20\/1eva2015ti_t4-lingotes-metales\/","title":{"rendered":"1Eva2015TI_T4 Lingotes metales"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">1ra Evaluaci\u00f3n I T\u00e9rmino 2015-2016. 7\/julio\/2015. ICM00158<\/h2>\n\n\n\n<p><strong>Tema 4<\/strong>. (25 puntos) Se tienen cuatro lingotes de 100 gramos, cada uno&nbsp; compuesto de la forma mostrada en la tabla.<\/p>\n\n\n\n<figure class=\"wp-block-image alignright size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"349\" height=\"174\" src=\"http:\/\/blog.espol.edu.ec\/algoritmos101\/files\/2017\/11\/lingotes-fundir.png\" alt=\"lingotes fundir\" class=\"wp-image-14107\" \/><\/figure>\n\n\n\n<p><\/p>\n\n\n\n<p>Se requiere determinar el peso en gramos que debe tomarse de cada uno de los cuatro lingotes anteriores para formar un nuevo lingote de 100 gramos que contenga:<\/p>\n\n\n\n<p>27 gramos de <strong>oro<\/strong>, 39.5 gramos de <strong>plata<\/strong>, 14 gramos de <strong>cobre<\/strong> y 19.5 gramos de <strong>esta\u00f1o<\/strong>.<\/p>\n\n\n\n<figure class=\"wp-block-table\"><table><thead><tr><th><\/th><th>Oro<\/th><th>Plata<\/th><th>Cobre<\/th><th>Esta\u00f1o<\/th><\/tr><\/thead><tbody><tr><th>Lingote 1<\/th><td>20<\/td><td>50<\/td><td>20<\/td><td>10<\/td><\/tr><tr><th>Lingote 2<\/th><td>30<\/td><td>40<\/td><td>10<\/td><td>20<\/td><\/tr><tr><th>Lingote 3<\/th><td>20<\/td><td>40<\/td><td>10<\/td><td>30<\/td><\/tr><tr><th>Lingote 4<\/th><td>50<\/td><td>20<\/td><td>20<\/td><td>10<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<p>a) Plantee un <strong>modelo<\/strong> matem\u00e1tico para describir este problema<\/p>\n\n\n\n<p>b) Describa un <strong>m\u00e9todo num\u00e9rico<\/strong> directo para encontrar la soluci\u00f3n.<br>Muestre evidencia suficiente del uso del m\u00e9todo num\u00e9rico<\/p>\n\n\n\n<p>c) Encuentre una <strong>cota para el error<\/strong> en la soluci\u00f3n calculada y comente.<\/p>\n\n\n\n<p><strong><em>R\u00fabrica<\/em><\/strong>: literal a (7 puntos), literal b (10 puntos), literal c (8 puntos)<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\" \/>\n\n\n\n<pre class=\"wp-block-code\"><code>compuesto = &#091;&#091; 20, 50, 20, 10],\n             &#091; 30, 40, 10, 20],\n             &#091; 20, 40, 10, 30],\n             &#091; 50, 20, 20, 10]]\nproporcion = &#091; 27, 39.5, 14, 19.5]<\/code><\/pre>\n","protected":false},"excerpt":{"rendered":"<p>1ra Evaluaci\u00f3n I T\u00e9rmino 2015-2016. 7\/julio\/2015. ICM00158 Tema 4. (25 puntos) Se tienen cuatro lingotes de 100 gramos, cada uno&nbsp; compuesto de la forma mostrada en la tabla. Se requiere determinar el peso en gramos que debe tomarse de cada uno de los cuatro lingotes anteriores para formar un nuevo lingote de 100 gramos que [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-mn","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[61],"class_list":["post-278","post","type-post","status-publish","format-standard","hentry","category-mn-1eva20","tag-matriciales-directos"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/278","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=278"}],"version-history":[{"count":2,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/278\/revisions"}],"predecessor-version":[{"id":14108,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/278\/revisions\/14108"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=278"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=278"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=278"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}