{"id":3098,"date":"2014-03-03T16:00:04","date_gmt":"2014-03-03T21:00:04","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/icm00794\/?p=3098"},"modified":"2026-04-05T06:48:20","modified_gmt":"2026-04-05T11:48:20","slug":"1eva2003tii_t1-cambiar-decimal-a-octal","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/fp-1eva10\/1eva2003tii_t1-cambiar-decimal-a-octal\/","title":{"rendered":"1Eva2003TII_T1 Cambiar Decimal a Octal"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">Parcial II T\u00e9rmino 2003 - 2004. Diciembre 09, 2003 \/ICM00794<\/h2>\n\n\n\n<p><strong>Tema 1<\/strong>. (25 puntos) Para realizar la conversi\u00f3n de un n\u00famero que est\u00e1 en una determinada base a su equivalente decimal, debe emplearse la siguiente regla:<\/p>\n\n\n\n<p class=\"has-text-align-center\">N = d<sub>i<\/sub>B<sup>i<\/sup> + . . . + d<sub>4<\/sub>B<sup>4<\/sup> + d<sub>3<\/sub>B<sup>3<\/sup> + d<sub>2<\/sub>B<sup>2<\/sup> + d<sub>1<\/sub>B<sup>1<\/sup> + d<sub>0<\/sub>B<sup>0 <\/sup><\/p>\n\n\n\n<figure class=\"wp-block-table\"><table><tbody><tr><td>En donde:<\/td><td>B: Base del sistema de numeraci\u00f3n original<br>d<sub>i<\/sub>: d\u00edgito en la posici\u00f3n i, con i = 0, 1, 2, ...<br>(0 es la posici\u00f3n menos significativa)<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<figure class=\"wp-block-image alignright size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"479\" height=\"331\" src=\"http:\/\/blog.espol.edu.ec\/algoritmos101\/files\/2014\/03\/contardedos01.png\" alt=\"contar octal con manos de caricatura\" class=\"wp-image-21921\" style=\"width:250px\" \/><\/figure>\n\n\n\n<pre class=\"wp-block-code\"><code>Ejemplo: para convertir <em><strong>764<\/strong><\/em><sub>8<\/sub> a base 10: \nN = <strong><em>7<\/em><\/strong> x 8<sup>2<\/sup> + <strong><em>6<\/em><\/strong> x 8<sup>1<\/sup> + <strong><em>4<\/em><\/strong> x 8<sup>0 <\/sup>= 500<sub>10<\/sub><\/code><\/pre>\n\n\n\n<figure class=\"wp-block-image alignleft size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"297\" height=\"162\" src=\"http:\/\/blog.espol.edu.ec\/algoritmos101\/files\/2014\/03\/contardedos02.png\" alt=\"contar decimales con dedos\" class=\"wp-image-21922\" \/><\/figure>\n\n\n\n<p>a) Escriba un Algoritmo que permita obtener el equivalente decimal (base 10) de un numero octal (entero de hasta 4 d\u00edgitos) ingresado por teclado.<\/p>\n\n\n\n<p>Suponga que ya existe la funci\u00f3n <strong>EsOctal(n)<\/strong>, cuyo par\u00e1metro <strong>n<\/strong> es un valor entero y retorna 2 posibles valores:<br><strong>1<\/strong> = verdadero,<br><strong>0<\/strong> = falso,<br>seg\u00fan sea que <strong>n<\/strong> es v\u00e1lido o no en ese sistema de numeraci\u00f3n.<\/p>\n\n\n\n<p>b) Realice la prueba de escritorio del algoritmo construido en el literal a) para el siguiente ejemplo: 1034<sub>8<\/sub> = N<sub>10<\/sub><\/p>\n\n\n\n<p><em><strong>Referencia<\/strong><\/em>: <a href=\"https:\/\/blog.espol.edu.ec\/algoritmos101\/fp-unidades\/fp-u03\/numero-binario-decimal\/\" data-type=\"post\" data-id=\"7907\">Bases Num\u00e9ricas Introducci\u00f3n<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Parcial II T\u00e9rmino 2003 - 2004. Diciembre 09, 2003 \/ICM00794 Tema 1. (25 puntos) Para realizar la conversi\u00f3n de un n\u00famero que est\u00e1 en una determinada base a su equivalente decimal, debe emplearse la siguiente regla: N = diBi + . . . + d4B4 + d3B3 + d2B2 + d1B1 + d0B0 En donde: [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-fp-ejercicios","format":"standard","meta":{"footnotes":""},"categories":[113],"tags":[155],"class_list":["post-3098","post","type-post","status-publish","format-standard","hentry","category-fp-1eva10","tag-funciones"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/3098","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=3098"}],"version-history":[{"count":4,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/3098\/revisions"}],"predecessor-version":[{"id":21923,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/3098\/revisions\/21923"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=3098"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=3098"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=3098"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}