{"id":4089,"date":"2019-08-29T11:09:05","date_gmt":"2019-08-29T16:09:05","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1013\/?p=4089"},"modified":"2025-12-13T03:50:50","modified_gmt":"2025-12-13T08:50:50","slug":"2eva2019ti_t2-pendulo-vertical","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/mn-2eva20\/2eva2019ti_t2-pendulo-vertical\/","title":{"rendered":"2Eva2019TI_T2 EDO P\u00e9ndulo vertical"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">2da Evaluaci\u00f3n I T\u00e9rmino 2019-2020. 27\/Agosto\/2019. MATG1013<\/h2>\n\n\n\n<p><strong>Tema 2<\/strong>. (40 Puntos) <\/p>\n\n\n\n<figure class=\"wp-block-image alignright size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"156\" height=\"186\" src=\"http:\/\/blog.espol.edu.ec\/algoritmos101\/files\/2019\/08\/penduloVertical01.png\" alt=\"p\u00e9ndulo Vertical\" class=\"wp-image-17457\" \/><\/figure>\n\n\n\n<p>Suponga que un p\u00e9ndulo tiene 0.6 m de Longitud, se desplaza\u00a0\u03b8 desde la posici\u00f3n vertical de equilibrio.<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> \\frac{d^2\\theta }{dt^2}+\\frac{g}{L}\\sin (\\theta)=0 <\/span>\n\n\n\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-28f84493 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\"><span class=\"wp-katex-eq katex-display\" data-display=\"true\"> 0&lt; t &lt; 1 <\/span>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> g = 9.81 \\frac{m}{s^2} <\/span>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\"><span class=\"wp-katex-eq katex-display\" data-display=\"true\"> \\theta(0) = \\frac{\\pi}{6} <\/span>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> \\theta '(0) = 0 <\/span>\n<\/div>\n<\/div>\n\n\n\n<p>a. Aproxime la soluci\u00f3n de la ecuaci\u00f3n para t = [0,1] con pasos de h=0.2<\/p>\n\n\n\n<p>b. Aproxime el valor del error<\/p>\n\n\n\n<p><strong>R\u00fabrica<\/strong>: literal a, expresiones (20 puntos), valor (10 puntos), literal b (10 puntos)<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\" \/>\n\n\n\n<p><strong>Referencia<\/strong>: [1] Ejercicio 5.9.8, Burden 9Ed, p338.<\/p>\n\n\n\n<p>[2] 2Eva_IT2010_T2 Movimiento angular<\/p>\n\n\n\n<p>[3] Professor of Physics Emeritus Walter Lewin.\u00a0 Lec 11 | 8.01 Physics I: Classical Mechanics, Fall 1999.<\/p>\n\n\n\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe loading=\"lazy\" title=\"For the Love of Physics - Walter Lewin - May 16, 2011\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/sJG-rXBbmCc?start=1354&feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" referrerpolicy=\"strict-origin-when-cross-origin\" allowfullscreen><\/iframe>\n<\/div><\/figure>\n\n\n\n<p class=\"title style-scope ytd-video-primary-info-renderer\">El P\u00c9NDULO SIMPLE NO es como te explicaron | F\u00edsica y Matem\u00e1ticas.&nbsp;Mates Mike<\/p>\n\n\n\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe loading=\"lazy\" title=\"El P\u00c9NDULO SIMPLE NO es como te explicaron | F\u00edsica y Matem\u00e1ticas\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/y5B6FCJlK9M?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" referrerpolicy=\"strict-origin-when-cross-origin\" allowfullscreen><\/iframe>\n<\/div><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>2da Evaluaci\u00f3n I T\u00e9rmino 2019-2020. 27\/Agosto\/2019. MATG1013 Tema 2. (40 Puntos) Suponga que un p\u00e9ndulo tiene 0.6 m de Longitud, se desplaza\u00a0\u03b8 desde la posici\u00f3n vertical de equilibrio. a. Aproxime la soluci\u00f3n de la ecuaci\u00f3n para t = [0,1] con pasos de h=0.2 b. Aproxime el valor del error R\u00fabrica: literal a, expresiones (20 puntos), [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-mn","format":"standard","meta":{"footnotes":""},"categories":[20],"tags":[56],"class_list":["post-4089","post","type-post","status-publish","format-standard","hentry","category-mn-2eva20","tag-edo"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/4089","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=4089"}],"version-history":[{"count":5,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/4089\/revisions"}],"predecessor-version":[{"id":17460,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/4089\/revisions\/17460"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=4089"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=4089"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=4089"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}