{"id":426,"date":"2017-11-09T13:30:38","date_gmt":"2017-11-09T18:30:38","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1013\/?p=426"},"modified":"2025-12-04T06:03:33","modified_gmt":"2025-12-04T11:03:33","slug":"1eva2009tii_t1_mn-precio-producto-lnx","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/mn-1eva10\/1eva2009tii_t1_mn-precio-producto-lnx\/","title":{"rendered":"1Eva2009TII_T1_MN Precio de producto ln(x)"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">1ra Evaluaci\u00f3n II T\u00e9rmino 2009-2010. 1\/Diciembre\/2009. ICM02188 M\u00e9todos Num\u00e9ricos<\/h2>\n\n\n\n<p><strong>Tema 1<\/strong>. (30 puntos) Suponga que el <strong>precio<\/strong> de un producto f(x) depende de la cantidad disponible x, con la siguiente relaci\u00f3n:<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> f(x) = 50 ln(x)<\/span>\n\n\n\n<p class=\"has-text-align-center\">10 \u2264 x \u2264 40<\/p>\n\n\n\n<p>a) Determine la <strong>cantidad<\/strong> del producto para que el <strong>precio<\/strong> sea igual a 160. Use el m\u00e9todo de <strong>Newton<\/strong> con una precisi\u00f3n 10<sup>-4<\/sup>,<\/p>\n\n\n\n<p>b) Encuentre un intervalo [a, b] tal que para cualquier aproximaci\u00f3n inicial que pertenezca a ese intervalo, el m\u00e9todo de Newton converge en el literal anterior.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>1ra Evaluaci\u00f3n II T\u00e9rmino 2009-2010. 1\/Diciembre\/2009. ICM02188 M\u00e9todos Num\u00e9ricos Tema 1. (30 puntos) Suponga que el precio de un producto f(x) depende de la cantidad disponible x, con la siguiente relaci\u00f3n: 10 \u2264 x \u2264 40 a) Determine la cantidad del producto para que el precio sea igual a 160. Use el m\u00e9todo de Newton [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-mn","format":"standard","meta":{"footnotes":""},"categories":[9],"tags":[66],"class_list":["post-426","post","type-post","status-publish","format-standard","hentry","category-mn-1eva10","tag-raices"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/426","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=426"}],"version-history":[{"count":4,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/426\/revisions"}],"predecessor-version":[{"id":13998,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/426\/revisions\/13998"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=426"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=426"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=426"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}