{"id":4429,"date":"2019-11-27T06:11:23","date_gmt":"2019-11-27T11:11:23","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1013\/?p=4429"},"modified":"2026-04-05T05:36:02","modified_gmt":"2026-04-05T10:36:02","slug":"1eva2019tii_t4-concentracion-de-quimico","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/mn-1eva20\/1eva2019tii_t4-concentracion-de-quimico\/","title":{"rendered":"1Eva2019TII_T4 Concentraci\u00f3n de qu\u00edmico"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">1ra Evaluaci\u00f3n II T\u00e9rmino 2019-2020. 26\/Noviembre\/2019. MATG1013<\/h2>\n\n\n\n<p><strong>Tema 4<\/strong>. (20 puntos) La siguiente ecuaci\u00f3n permite calcular la concentraci\u00f3n de un qu\u00edmico en un reactor, donde se tiene una mezcla completa.<\/p>\n\n\n\n<figure class=\"wp-block-image alignright size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"226\" height=\"275\" src=\"http:\/\/blog.espol.edu.ec\/algoritmos101\/files\/2019\/11\/reactorQuimico01.png\" alt=\"reactor Quimico\" class=\"wp-image-14179\" \/><\/figure>\n\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\">C = C_{ent} ( 1 - e^{-0.04t})+C_{0} e^{-0.03t}<\/span>\n\n\n\n<p>Si la concentraci\u00f3n inicial es C<sub>0<\/sub> = 4 y la concentraci\u00f3n de entrada es C<sub>ent<\/sub> = 10, use el m\u00e9todo de Newton-Raphson con t<sub>0<\/sub> = 0, para aproximar el tiempo requerido para que el valor de <strong>C<\/strong> sea 93% de C<sub>ent<\/sub>.<\/p>\n\n\n\n<p>Encuentre un intervalo en donde la convergencia est\u00e1 garantizada.<\/p>\n\n\n\n<p><strong><em>R\u00fabrica<\/em><\/strong>: intervalo (5 puntos), iteraciones (10 puntos), convergencia (5 puntos)<\/p>\n","protected":false},"excerpt":{"rendered":"<p>1ra Evaluaci\u00f3n II T\u00e9rmino 2019-2020. 26\/Noviembre\/2019. MATG1013 Tema 4. (20 puntos) La siguiente ecuaci\u00f3n permite calcular la concentraci\u00f3n de un qu\u00edmico en un reactor, donde se tiene una mezcla completa. Si la concentraci\u00f3n inicial es C0 = 4 y la concentraci\u00f3n de entrada es Cent = 10, use el m\u00e9todo de Newton-Raphson con t0 = [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-mn","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[66],"class_list":["post-4429","post","type-post","status-publish","format-standard","hentry","category-mn-1eva20","tag-raices"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/4429","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=4429"}],"version-history":[{"count":4,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/4429\/revisions"}],"predecessor-version":[{"id":14181,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/4429\/revisions\/14181"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=4429"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=4429"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=4429"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}