{"id":4738,"date":"2020-01-29T10:22:04","date_gmt":"2020-01-29T15:22:04","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1013\/?p=4738"},"modified":"2025-12-13T04:03:16","modified_gmt":"2025-12-13T09:03:16","slug":"2eva2019tii_t4-integrar-con-cuadratura-de-gauss","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/mn-2eva20\/2eva2019tii_t4-integrar-con-cuadratura-de-gauss\/","title":{"rendered":"2Eva2019TII_T4 Integrar con Cuadratura de Gauss"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">2da Evaluaci\u00f3n II T\u00e9rmino 2019-2020. 28\/Enero\/2020. MATG1013<\/h2>\n\n\n\n<p><strong>Tema 3<\/strong>. (25 Puntos) Considere la funci\u00f3n f con regla de correspondencia:<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> f(x) = x ln(x) <\/span>\n\n\n\n<p>Se desea aproximar el valor del integral I en el intervalo [1,4]<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> I = \\int_a^b f(x) dx <\/span>\n\n\n\n<p>a) Use el m\u00e9todo de Cuadratura de Gauss con 2 t\u00e9rminos para aproximar el valor de I en el intervalo [1,4]<\/p>\n\n\n\n<p>Usando el m\u00e9todo compuesto de Simpson:<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> I = I_s - \\frac{(b-a)}{180}h^4 f^{(4)} (\\xi) ; \\xi \\in[a,b] <\/span>\n\n\n\n<p>Donde Is es el valor aproximado de I y h la longitud de cada intervalo.<\/p>\n\n\n\n<p>b) Determine el m\u00ednimo n\u00famero de subintervalos que permita alcanzar una tolerancia de 0.0001. <strong>NO considere errores de redondeo<\/strong>.<\/p>\n\n\n\n<p><strong>R\u00fabrica<\/strong>: literal a (10 puntos), literal b (15 puntos)<\/p>\n","protected":false},"excerpt":{"rendered":"<p>2da Evaluaci\u00f3n II T\u00e9rmino 2019-2020. 28\/Enero\/2020. MATG1013 Tema 3. (25 Puntos) Considere la funci\u00f3n f con regla de correspondencia: Se desea aproximar el valor del integral I en el intervalo [1,4] a) Use el m\u00e9todo de Cuadratura de Gauss con 2 t\u00e9rminos para aproximar el valor de I en el intervalo [1,4] Usando el m\u00e9todo [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-mn","format":"standard","meta":{"footnotes":""},"categories":[20],"tags":[59],"class_list":["post-4738","post","type-post","status-publish","format-standard","hentry","category-mn-2eva20","tag-integracion-numerica"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/4738","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=4738"}],"version-history":[{"count":3,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/4738\/revisions"}],"predecessor-version":[{"id":17472,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/4738\/revisions\/17472"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=4738"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=4738"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=4738"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}