{"id":486,"date":"2017-11-08T16:40:02","date_gmt":"2017-11-08T21:40:02","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1013\/?p=486"},"modified":"2025-12-04T06:28:35","modified_gmt":"2025-12-04T11:28:35","slug":"1eva2008tii_t3_mn-ganancia-en-inversion","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/mn-1eva10\/1eva2008tii_t3_mn-ganancia-en-inversion\/","title":{"rendered":"1Eva2008TII_T3_MN Ganancia en inversi\u00f3n"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">1ra Evaluaci\u00f3n II T\u00e9rmino 2008-2009. 9\/Diciembre\/2008. ICM02188 M\u00e9todos Num\u00e9ricos<\/h2>\n\n\n\n<p><strong>Tema 3<\/strong>. <\/p>\n\n\n\n<figure class=\"wp-block-image alignright size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"313\" height=\"313\" src=\"http:\/\/blog.espol.edu.ec\/algoritmos101\/files\/2017\/07\/inversionGanancia01.png\" alt=\"inversi\u00f3n Ganancia 01\" class=\"wp-image-13545\" style=\"width:200px\" \/><\/figure>\n\n\n\n<p>Se dispone de los datos (<strong>x<\/strong>, <strong>f<\/strong>(<strong>x<\/strong>)), en donde <strong>x<\/strong> es un valor de inversi\u00f3n y <strong>f<\/strong>(<strong>x<\/strong>) es un valor de ganancia, ambos en miles de d\u00f3lares:<\/p>\n\n\n\n<figure class=\"wp-block-table aligncenter\"><table><thead><tr><th>inversi\u00f3n<\/th><th>ganancia<\/th><\/tr><\/thead><tbody><tr><td>3.2<\/td><td>5.12<\/td><\/tr><tr><td>3.8<\/td><td>6.42<\/td><\/tr><tr><td>4.2<\/td><td>7.25<\/td><\/tr><tr><td>4.5<\/td><td>6.85<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<p>para analizar \u00e9ste comportamiento se propone usar el siguiente modelo:<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> f(x) = a_1 x^3 + a_2 x^2 + a_3 x + a_4<\/span>\n\n\n\n<figure class=\"wp-block-image alignright size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"640\" height=\"480\" src=\"http:\/\/blog.espol.edu.ec\/algoritmos101\/files\/2017\/11\/GananciaInversion01.png\" alt=\"Ganancia Inversi\u00f3n gr\u00e1fica curva ejercicio\" class=\"wp-image-14015\" \/><\/figure>\n\n\n\n<p>a) Sustituya cada dato (<strong>x<\/strong>, <strong>f<\/strong>(<strong>x<\/strong>)) en el modelo y obtenga un sistema de ecuaciones lineales. <\/p>\n\n\n\n<p>b) Obtenga los coeficientes a<sub>i<\/sub> resolviendo el sistema lineal con un m\u00e9todo num\u00e9rico directo.<\/p>\n\n\n\n<p>c) Con el modelo <strong>f<\/strong>(<strong>x<\/strong>), use el m\u00e9todo de la Bisecci\u00f3n para calcular cu\u00e1nto debe invertirse si se desea que la ganancia sea de 6.0 (miles de d\u00f3lares).<\/p>\n\n\n\n<p><br><strong><em>Precisi\u00f3n<\/em><\/strong>: dos decimales exactos.<\/p>\n\n\n\n<div style=\"height:73px\" aria-hidden=\"true\" class=\"wp-block-spacer\"><\/div>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\" \/>\n\n\n\n<pre class=\"wp-block-code\"><code>xi = &#091;3.2 , 3.8 , 4.2 , 4.5 ]\nfi = &#091;5.12, 6.42, 7.25, 6.85]<\/code><\/pre>\n","protected":false},"excerpt":{"rendered":"<p>1ra Evaluaci\u00f3n II T\u00e9rmino 2008-2009. 9\/Diciembre\/2008. ICM02188 M\u00e9todos Num\u00e9ricos Tema 3. Se dispone de los datos (x, f(x)), en donde x es un valor de inversi\u00f3n y f(x) es un valor de ganancia, ambos en miles de d\u00f3lares: inversi\u00f3n ganancia 3.2 5.12 3.8 6.42 4.2 7.25 4.5 6.85 para analizar \u00e9ste comportamiento se propone usar [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-mn","format":"standard","meta":{"footnotes":""},"categories":[9],"tags":[60],"class_list":["post-486","post","type-post","status-publish","format-standard","hentry","category-mn-1eva10","tag-interpolacion-polinomica"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/486","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=486"}],"version-history":[{"count":5,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/486\/revisions"}],"predecessor-version":[{"id":14017,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/486\/revisions\/14017"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=486"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=486"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=486"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}