{"id":496,"date":"2017-12-02T07:05:52","date_gmt":"2017-12-02T12:05:52","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1013\/?p=496"},"modified":"2026-04-05T05:43:16","modified_gmt":"2026-04-05T10:43:16","slug":"1eva2017ti_t1-caida-de-paracaidista","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/mn-1eva20\/1eva2017ti_t1-caida-de-paracaidista\/","title":{"rendered":"1Eva2017TI_T1 Caida de paracaidista"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">1ra Evaluaci\u00f3n I T\u00e9rmino 2017-2018. 26\/junio\/2017. MATG1013<\/h2>\n\n\n\n<p><strong>Tema 1<\/strong>. (25 puntos) La velocidad de ca\u00edda de un paracaidista puede calcularse con la ecuaci\u00f3n<\/p>\n\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> v(t) = \\frac{gm}{c} \\big( 1- e^{-(c\/m)t} \\big) <\/span>\n\n\n\n<figure class=\"wp-block-image alignright size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"520\" height=\"344\" src=\"http:\/\/blog.espol.edu.ec\/algoritmos101\/files\/2017\/12\/caidaparacaidas01.png\" alt=\"ca\u00edda paraca\u00eddas 01\" class=\"wp-image-14115\" \/><\/figure>\n\n\n\n<p>donde:<br> <strong>g<\/strong> = 9.8, <br><strong>m<\/strong> = 50\u00b12 <br><strong>c<\/strong> = 12.5\u00b11.5<\/p>\n\n\n\n<p>a) Construya un polinomio con los puntos <br><strong>t<\/strong> = 0, 3, 5.<\/p>\n\n\n\n<p>b) Eval\u00fae el polinomio para <strong>t<\/strong> = 4 y estime el error de truncamiento y el error propagado.<\/p>\n\n\n\n<p><em><strong>R\u00fabrica<\/strong><\/em>: Construcci\u00f3n del polinomio hasta 10 puntos, Evaluar el polinomio hasta 5 puntos, estimar el error por truncamiento hasta 5 puntos y estimar el error propagado hasta 5 puntos.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>1ra Evaluaci\u00f3n I T\u00e9rmino 2017-2018. 26\/junio\/2017. MATG1013 Tema 1. (25 puntos) La velocidad de ca\u00edda de un paracaidista puede calcularse con la ecuaci\u00f3n donde: g = 9.8, m = 50\u00b12 c = 12.5\u00b11.5 a) Construya un polinomio con los puntos t = 0, 3, 5. b) Eval\u00fae el polinomio para t = 4 y estime [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-mn","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[60],"class_list":["post-496","post","type-post","status-publish","format-standard","hentry","category-mn-1eva20","tag-interpolacion-polinomica"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/496","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=496"}],"version-history":[{"count":6,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/496\/revisions"}],"predecessor-version":[{"id":14120,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/496\/revisions\/14120"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=496"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=496"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=496"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}