{"id":505,"date":"2017-12-02T07:34:05","date_gmt":"2017-12-02T12:34:05","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1013\/?p=505"},"modified":"2026-04-05T05:42:47","modified_gmt":"2026-04-05T10:42:47","slug":"1eva2017ti_t3-sistema-no-lineal","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/mn-1eva20\/1eva2017ti_t3-sistema-no-lineal\/","title":{"rendered":"1Eva2017TI_T3 Sistema no lineal"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">1ra Evaluaci\u00f3n I T\u00e9rmino 2017-2018. 26\/junio\/2017. MATG1013<\/h2>\n\n\n\n<p><strong>Tema 3<\/strong>. (25 puntos) 3. El sistema no lineal<\/p>\n\n\n\n<p class=\"has-text-align-center\">-x(x + 1) + 2y = 18<br>x - 1 + (y - 6)<sup>2<\/sup> = 25<\/p>\n\n\n\n<p>tiene dos soluciones.<\/p>\n\n\n\n<p>a) Aproxime gr\u00e1ficamente las soluciones<\/p>\n\n\n\n<p>b) Utilice el m\u00e9todo de Newton Raphson en una variable para aproximar una soluci\u00f3n, (realice tres iteraciones).<\/p>\n\n\n\n<p>c) Utilice el m\u00e9todo de Newton Raphson en dos variables para aproximar una soluci\u00f3n, (realice tres iteraciones) y estime el error de la segunda iteraci\u00f3n.<\/p>\n\n\n\n<p><strong><em>R\u00fabrica<\/em><\/strong>: Soluciones gr\u00e1ficas hasta 5 puntos, M\u00e9todo de Newton hasta 10 puntos, M\u00e9todo que involucra al jacobiano hasta 10 puntos.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>1ra Evaluaci\u00f3n I T\u00e9rmino 2017-2018. 26\/junio\/2017. MATG1013 Tema 3. (25 puntos) 3. El sistema no lineal -x(x + 1) + 2y = 18x - 1 + (y - 6)2 = 25 tiene dos soluciones. a) Aproxime gr\u00e1ficamente las soluciones b) Utilice el m\u00e9todo de Newton Raphson en una variable para aproximar una soluci\u00f3n, (realice tres [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-mn","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[66],"class_list":["post-505","post","type-post","status-publish","format-standard","hentry","category-mn-1eva20","tag-raices"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/505","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=505"}],"version-history":[{"count":2,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/505\/revisions"}],"predecessor-version":[{"id":14127,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/505\/revisions\/14127"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=505"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=505"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=505"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}