{"id":629,"date":"2017-12-08T18:00:46","date_gmt":"2017-12-08T23:00:46","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1013\/?p=629"},"modified":"2025-12-13T10:41:41","modified_gmt":"2025-12-13T15:41:41","slug":"3eva2008tii_t1-corriente-en-circuito","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/mn-3eva10\/3eva2008tii_t1-corriente-en-circuito\/","title":{"rendered":"3Eva2008TII_T1 Corriente en circuito"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">3ra Evaluaci\u00f3n II T\u00e9rmino 2008-2009. 3\/Marzo\/2009. ICM00158<\/h2>\n\n\n\n<p><strong>Tema 1<\/strong>. Mediante una investigaci\u00f3n se ha logrado determinar que la intensidad de corriente i(t) en cierto circuito sometido a un campo el\u00e9ctrico variable en el tiempo responde a la ecuaci\u00f3n integro-diferencial:<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> \\frac{\\delta i}{\\delta t} - \\int_0^t \\frac{e^u}{u+1} \\delta u -t i(t) = 0 <\/span>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> t \\in [0,1]; y(0)=1<\/span>\n\n\n\n<p>Determinar cu\u00e1l es la intensidad de corriente en los instantes <strong>t<\/strong>=0.25 y <strong>t<\/strong>=0.5 segundos.<\/p>\n\n\n\n<p>Utilice el m\u00e9todo de Runge-Kutta para resolver la ecuaci\u00f3n diferencial y Trapecios <strong>n<\/strong>=2 para resolver las integrales que se generan<\/p>\n","protected":false},"excerpt":{"rendered":"<p>3ra Evaluaci\u00f3n II T\u00e9rmino 2008-2009. 3\/Marzo\/2009. ICM00158 Tema 1. Mediante una investigaci\u00f3n se ha logrado determinar que la intensidad de corriente i(t) en cierto circuito sometido a un campo el\u00e9ctrico variable en el tiempo responde a la ecuaci\u00f3n integro-diferencial: Determinar cu\u00e1l es la intensidad de corriente en los instantes t=0.25 y t=0.5 segundos. Utilice el [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-mn","format":"standard","meta":{"footnotes":""},"categories":[25],"tags":[56],"class_list":["post-629","post","type-post","status-publish","format-standard","hentry","category-mn-3eva10","tag-edo"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/629","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=629"}],"version-history":[{"count":2,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/629\/revisions"}],"predecessor-version":[{"id":17762,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/629\/revisions\/17762"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=629"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=629"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=629"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}