{"id":637,"date":"2017-12-08T18:10:28","date_gmt":"2017-12-08T23:10:28","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1013\/?p=637"},"modified":"2025-12-13T10:47:26","modified_gmt":"2025-12-13T15:47:26","slug":"3eva2008tii_t3-edo-d2y-dx2-con-diferencias-finitasdiferencial","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/mn-3eva10\/3eva2008tii_t3-edo-d2y-dx2-con-diferencias-finitasdiferencial\/","title":{"rendered":"3Eva2008TII_T3 EDO d2y\/dx2 con diferencias finitas"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">3ra Evaluaci\u00f3n II T\u00e9rmino 2008-2009. 3\/Marzo\/2009. ICM00158<\/h2>\n\n\n\n<p><strong>Tema 3<\/strong>. Dada la siguiente ecuaci\u00f3n diferencial, resuelva usando el m\u00e9todo de las diferencias finitas:<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> y'' + (x+1)y'-2y = (1-x^2)e^{-x^2} <\/span>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> 0 \\leq x \\leq 1 <\/span>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> y(0)=-1, y(1)=0 <\/span>\n\n\n\n<p>a. Aplique el algoritmo con h = 0.2<\/p>\n\n\n\n<p>b. Escriba el sistema de ecuaciones y obtenga la soluci\u00f3n con un m\u00e9todo iterativo con 10<sup>-3<\/sup> como tolerancia para detener el proceso<\/p>\n","protected":false},"excerpt":{"rendered":"<p>3ra Evaluaci\u00f3n II T\u00e9rmino 2008-2009. 3\/Marzo\/2009. ICM00158 Tema 3. Dada la siguiente ecuaci\u00f3n diferencial, resuelva usando el m\u00e9todo de las diferencias finitas: a. Aplique el algoritmo con h = 0.2 b. Escriba el sistema de ecuaciones y obtenga la soluci\u00f3n con un m\u00e9todo iterativo con 10-3 como tolerancia para detener el proceso<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-mn","format":"standard","meta":{"footnotes":""},"categories":[25],"tags":[56],"class_list":["post-637","post","type-post","status-publish","format-standard","hentry","category-mn-3eva10","tag-edo"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/637","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=637"}],"version-history":[{"count":2,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/637\/revisions"}],"predecessor-version":[{"id":17768,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/637\/revisions\/17768"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=637"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=637"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=637"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}