{"id":642,"date":"2017-12-08T23:42:14","date_gmt":"2017-12-09T04:42:14","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1013\/?p=642"},"modified":"2025-12-12T09:15:46","modified_gmt":"2025-12-12T14:15:46","slug":"2eva2008ti_t1_an-resistencia-de-material","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/mn-2eva10\/2eva2008ti_t1_an-resistencia-de-material\/","title":{"rendered":"2Eva2008TI_T1_AN EDO Resistencia de material"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">2da Evaluaci\u00f3n I T\u00e9rmino 2008-2009. 2\/Septiembre\/2008. An\u00e1lisis Num\u00e9rico<\/h2>\n\n\n\n<p><strong>Tema 1<\/strong>. Mediante una investigaci\u00f3n se ha logrado determinar que la resistencia de cierto material sometido a un esfuerzo variable en el tiempo responde a la ecuaci\u00f3n \u00edntegro-diferencial:<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> y'- \\int_0^t \\frac{e^u}{u} \\delta u -ty =0<\/span>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> t \\in [0,1]; y(0)=1<\/span>\n\n\n\n<p>Determinar cu\u00e1l es la resistencia en los instantes <strong>t<\/strong> = 0.25, 0.5, 0.75 y 1 segundos.<\/p>\n\n\n\n<p>Utilice el m\u00e9todo de Euler para resolver la ecuaci\u00f3n diferencial y trapecios <strong>n<\/strong>=2 para resolver las integrales que se generan.<\/p>\n\n\n\n<p>&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>2da Evaluaci\u00f3n I T\u00e9rmino 2008-2009. 2\/Septiembre\/2008. An\u00e1lisis Num\u00e9rico Tema 1. Mediante una investigaci\u00f3n se ha logrado determinar que la resistencia de cierto material sometido a un esfuerzo variable en el tiempo responde a la ecuaci\u00f3n \u00edntegro-diferencial: Determinar cu\u00e1l es la resistencia en los instantes t = 0.25, 0.5, 0.75 y 1 segundos. Utilice el m\u00e9todo [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-mn","format":"standard","meta":{"footnotes":""},"categories":[17],"tags":[56],"class_list":["post-642","post","type-post","status-publish","format-standard","hentry","category-mn-2eva10","tag-edo"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/642","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=642"}],"version-history":[{"count":2,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/642\/revisions"}],"predecessor-version":[{"id":17268,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/642\/revisions\/17268"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=642"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=642"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=642"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}