{"id":670,"date":"2017-12-08T00:48:04","date_gmt":"2017-12-08T05:48:04","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1013\/?p=670"},"modified":"2025-12-12T09:51:52","modified_gmt":"2025-12-12T14:51:52","slug":"2eva2008ti_t3_mn-estimar-utilidades","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/mn-2eva10\/2eva2008ti_t3_mn-estimar-utilidades\/","title":{"rendered":"2Eva2008TI_T3_MN Estimar utilidades"},"content":{"rendered":"\n<h2 class=\"wp-block-heading is-style-default\">2da Evaluaci\u00f3n I T\u00e9rmino 2008-2009. ICM02188 M\u00e9todos Num\u00e9ricos<\/h2>\n\n\n\n<p><strong>Tema 3<\/strong>. Se tienen las <strong>utilidad<\/strong>es anuales de una empresa cada 3 a\u00f1os.<\/p>\n\n\n\n<figure class=\"wp-block-table\"><table><tbody><tr><td><strong>\u00a0A\u00f1o<\/strong><\/td><td>&nbsp;0<\/td><td>&nbsp;3<\/td><td>&nbsp;6<\/td><td>&nbsp;9<\/td><td>12<\/td><\/tr><tr><td><strong>\u00a0Utilidad Anual<\/strong><\/td><td>&nbsp;0<\/td><td>&nbsp;16500<\/td><td>&nbsp;14520<\/td><td>&nbsp;1540<\/td><td>&nbsp;14690<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<p>a. Encuentre el <strong>trazador c\u00fabico natural<\/strong> que se ajusta a los datos de la tabla. Resuelva el sistema de ecuaciones con el m\u00e9todo de Gauss=Seidel con un error menor a 10<sup>-3<\/sup><\/p>\n\n\n\n<p>b. Aproxime el <strong>\u00e1rea bajo la curva<\/strong> de 0 a 12 a\u00f1os aplicando una vez la Cuadratura de Gauss.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\" \/>\n\n\n\n<pre class=\"wp-block-code\"><code>anio = &#091; 0, 3, 6, 9, 12]\nutilidad = &#091; 0, 16500, 14520, 1540, 14690]<\/code><\/pre>\n","protected":false},"excerpt":{"rendered":"<p>2da Evaluaci\u00f3n I T\u00e9rmino 2008-2009. ICM02188 M\u00e9todos Num\u00e9ricos Tema 3. Se tienen las utilidades anuales de una empresa cada 3 a\u00f1os. \u00a0A\u00f1o &nbsp;0 &nbsp;3 &nbsp;6 &nbsp;9 12 \u00a0Utilidad Anual &nbsp;0 &nbsp;16500 &nbsp;14520 &nbsp;1540 &nbsp;14690 a. Encuentre el trazador c\u00fabico natural que se ajusta a los datos de la tabla. Resuelva el sistema de ecuaciones con [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-mn","format":"standard","meta":{"footnotes":""},"categories":[17],"tags":[59,60],"class_list":["post-670","post","type-post","status-publish","format-standard","hentry","category-mn-2eva10","tag-integracion-numerica","tag-interpolacion-polinomica"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/670","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=670"}],"version-history":[{"count":2,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/670\/revisions"}],"predecessor-version":[{"id":17289,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/670\/revisions\/17289"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=670"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=670"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=670"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}