{"id":691,"date":"2017-12-09T15:05:32","date_gmt":"2017-12-09T20:05:32","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1013\/?p=691"},"modified":"2025-12-13T10:50:04","modified_gmt":"2025-12-13T15:50:04","slug":"3eva2009ti_t2-edo-taylor-senox","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/mn-3eva10\/3eva2009ti_t2-edo-taylor-senox\/","title":{"rendered":"3Eva2009TI_T2 EDO Taylor Seno(x)"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">3ra Evaluaci\u00f3n I T\u00e9rmino 2009-2010. 15\/Septiembre\/2009. ICM00158<\/h2>\n\n\n\n<p><strong>Tema 2<\/strong>. (25 puntos) Resolver la ecuaci\u00f3n diferencial usando el m\u00e9todo de Taylor con n=2:<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> xy'+ 2y = \\sin (x) <\/span>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> \\frac{\\pi}{2} \\leq x \\leq \\frac{3\\pi}{2} <\/span>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> y\\Big(\\frac{\\pi}{2} \\Big) = 1<\/span>\n\n\n\n<p>a. Establecer el algoritmo correspondiente para la ecuaci\u00f3n dada<\/p>\n\n\n\n<p>b. Escribir la tabla de resultados para <strong>h<\/strong> = \u03c0\/10<\/p>\n\n\n\n<p><em><strong>R\u00fabrica<\/strong><\/em>: Determinaci\u00f3n correcta de f(x,y(x<sub>i<\/sub>) )(2.5 puntos), establecimiento del algoritmo de Taylor (12.5 puntos), Soluci\u00f3n num\u00e9rica (10 puntos)<\/p>\n","protected":false},"excerpt":{"rendered":"<p>3ra Evaluaci\u00f3n I T\u00e9rmino 2009-2010. 15\/Septiembre\/2009. ICM00158 Tema 2. (25 puntos) Resolver la ecuaci\u00f3n diferencial usando el m\u00e9todo de Taylor con n=2: a. Establecer el algoritmo correspondiente para la ecuaci\u00f3n dada b. Escribir la tabla de resultados para h = \u03c0\/10 R\u00fabrica: Determinaci\u00f3n correcta de f(x,y(xi) )(2.5 puntos), establecimiento del algoritmo de Taylor (12.5 puntos), [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-mn","format":"standard","meta":{"footnotes":""},"categories":[25],"tags":[56],"class_list":["post-691","post","type-post","status-publish","format-standard","hentry","category-mn-3eva10","tag-edo"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/691","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=691"}],"version-history":[{"count":2,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/691\/revisions"}],"predecessor-version":[{"id":17772,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/691\/revisions\/17772"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=691"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=691"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=691"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}