{"id":708,"date":"2017-12-09T07:32:13","date_gmt":"2017-12-09T12:32:13","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1013\/?p=708"},"modified":"2025-12-12T11:04:42","modified_gmt":"2025-12-12T16:04:42","slug":"2eva2009ti_t2_an-edp-hiperbolica","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/mn-2eva10\/2eva2009ti_t2_an-edp-hiperbolica\/","title":{"rendered":"2Eva2009TI_T2_AN EDP hiperb\u00f3lica"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">2da Evaluaci\u00f3n I T\u00e9rmino 2009-2010. 1\/Septiembre\/2009. An\u00e1lisis Num\u00e9rico<\/h2>\n\n\n\n<p><strong>Tema 2<\/strong>. (20 puntos) Dada la ecuaci\u00f3n hiperb\u00f3lica<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> \\frac{\\partial ^2 u}{\\partial t^2} - \\frac{\\partial ^2 u}{\\partial x^2} = 0 <\/span>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> 0 &lt; x  0 <\/span>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> \\begin{cases} u(0,t) = u(1,t) = 0 , &amp; t&gt;0 \\\\ u(x,0) = \\sin (2\\pi x), &amp; 0 \\leq x \\leq 1 \\\\ \\frac{\\delta u}{\\delta t} (x,0) = 2 \\pi \\sin (2\\pi x) , &amp; 0 \\leq x \\leq 1\\end{cases} <\/span>\n\n\n\n<p>Aproximar u(x,t) para t=0.8, con h=k=0.2<\/p>\n\n\n\n<p><strong>R\u00fabrica<\/strong>: Establecer el m\u00e9todo de diferencia centrada y condiciones de frontera (5 puntos), determinar \u03c9<sub>i1<\/sub> (5 puntos), aproximaci\u00f3n de u(x,t) en t=0.8 (10 puntos)<\/p>\n","protected":false},"excerpt":{"rendered":"<p>2da Evaluaci\u00f3n I T\u00e9rmino 2009-2010. 1\/Septiembre\/2009. An\u00e1lisis Num\u00e9rico Tema 2. (20 puntos) Dada la ecuaci\u00f3n hiperb\u00f3lica Aproximar u(x,t) para t=0.8, con h=k=0.2 R\u00fabrica: Establecer el m\u00e9todo de diferencia centrada y condiciones de frontera (5 puntos), determinar \u03c9i1 (5 puntos), aproximaci\u00f3n de u(x,t) en t=0.8 (10 puntos)<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-mn","format":"standard","meta":{"footnotes":""},"categories":[17],"tags":[57],"class_list":["post-708","post","type-post","status-publish","format-standard","hentry","category-mn-2eva10","tag-edp"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/708","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=708"}],"version-history":[{"count":3,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/708\/revisions"}],"predecessor-version":[{"id":17303,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/708\/revisions\/17303"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=708"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=708"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=708"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}