{"id":734,"date":"2017-11-10T14:05:15","date_gmt":"2017-11-10T19:05:15","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1013\/?p=734"},"modified":"2025-12-12T11:12:27","modified_gmt":"2025-12-12T16:12:27","slug":"2eva2010ti_t2-movimiento-angular","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/mn-2eva10\/2eva2010ti_t2-movimiento-angular\/","title":{"rendered":"2Eva2010TI_T2 EDO Movimiento angular"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">2da Evaluaci\u00f3n I T\u00e9rmino 2010-2011. 31\/Agosto\/2010. ICM00158<\/h2>\n\n\n\n<p><strong>Tema 2<\/strong>. La ecuaci\u00f3n de un movimiento angular est\u00e1 dada por<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> y'' + 10 \\sin (y) =0 <\/span>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> 0\\leq t \\leq 1 <\/span>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\">y(0)=0, y'(0)=0.1 <\/span>\n\n\n\n<p>Empleando el m\u00e9todo de Runge-Kutta de 4to orden generalizado y un paso de 0.25, aproximar la soluci\u00f3n de la ecuaci\u00f3n en <strong>t<\/strong>=0.50<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\" \/>\n\n\n\n<p><strong>Referencia<\/strong>:&nbsp; Chapra 28.4 p842 pdf 866<\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"525\" height=\"212\" src=\"http:\/\/blog.espol.edu.ec\/algoritmos101\/files\/2017\/11\/columpioCasaArbolBanosEcuador01.png\" alt=\"columpio Casa \u00c1rbol Ba\u00f1os Ecuador\" class=\"wp-image-17315\" \/><figcaption class=\"wp-element-caption\">BA\u00d1OS DE AGUA SANTA Y EL COLUMPIO DEL FIN DEL MUNDO<\/figcaption><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>2da Evaluaci\u00f3n I T\u00e9rmino 2010-2011. 31\/Agosto\/2010. ICM00158 Tema 2. La ecuaci\u00f3n de un movimiento angular est\u00e1 dada por Empleando el m\u00e9todo de Runge-Kutta de 4to orden generalizado y un paso de 0.25, aproximar la soluci\u00f3n de la ecuaci\u00f3n en t=0.50 Referencia:&nbsp; Chapra 28.4 p842 pdf 866<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-mn","format":"standard","meta":{"footnotes":""},"categories":[17],"tags":[56],"class_list":["post-734","post","type-post","status-publish","format-standard","hentry","category-mn-2eva10","tag-edo"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/734","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=734"}],"version-history":[{"count":4,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/734\/revisions"}],"predecessor-version":[{"id":17317,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/734\/revisions\/17317"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=734"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=734"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=734"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}