{"id":740,"date":"2017-12-10T15:00:07","date_gmt":"2017-12-10T20:00:07","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1013\/?p=740"},"modified":"2025-12-13T11:04:05","modified_gmt":"2025-12-13T16:04:05","slug":"3eva2010ti_t1-envase-cilindrico","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/mn-3eva10\/3eva2010ti_t1-envase-cilindrico\/","title":{"rendered":"3Eva2010TI_T1 Envase cil\u00edndrico"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">3ra Evaluaci\u00f3n I T\u00e9rmino 2010-2011. 14\/Septiembre\/2010. ICM00158<\/h2>\n\n\n\n<figure class=\"wp-block-image alignright size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"233\" height=\"344\" src=\"http:\/\/blog.espol.edu.ec\/algoritmos101\/files\/2017\/12\/envaseCilindro01.png\" alt=\"envase Cilindro \" class=\"wp-image-17782\" \/><\/figure>\n\n\n\n<p><strong>Tema 1<\/strong>. Un envase de lata con forma de cilindro circular recto, ser\u00e1 construido para contener 1000 cm<sup>3<\/sup>. <\/p>\n\n\n\n<p>Las partes superior e inferior circulares del envase deben tener un radio de 0.25 mayor que el radio de \u00e9ste, de manera que el excedente pueda usarse para formar un sello con el cuerpo principal.<\/p>\n\n\n\n<p>La hoja de material con la que se forme dicho cuerpo, debe ser tambi\u00e9n de 0.25 cm m\u00e1s larga que la circunferencia del envase, de manera que se pueda formar un sello.<\/p>\n\n\n\n<p>Encuentre con un error de 10<sup>-4<\/sup> la cantidad m\u00ednima de material para construir dicha lata.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\" \/>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"309\" height=\"280\" src=\"http:\/\/blog.espol.edu.ec\/algoritmos101\/files\/2017\/12\/lataabierta01.png\" alt=\"lata abierta metal\" class=\"wp-image-17784\" \/><\/figure>\n\n\n\n<p><strong>Referencias<\/strong>: Burden Cap2.6 Ejercicio 11 9Ed p101<\/p>\n\n\n\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe loading=\"lazy\" title=\"Como lo hacen - Latas de aluminio - DiscoveryMAX\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/5zVCRT8-M2c?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" referrerpolicy=\"strict-origin-when-cross-origin\" allowfullscreen><\/iframe>\n<\/div><\/figure>\n\n\n\n<p>&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>3ra Evaluaci\u00f3n I T\u00e9rmino 2010-2011. 14\/Septiembre\/2010. ICM00158 Tema 1. Un envase de lata con forma de cilindro circular recto, ser\u00e1 construido para contener 1000 cm3. Las partes superior e inferior circulares del envase deben tener un radio de 0.25 mayor que el radio de \u00e9ste, de manera que el excedente pueda usarse para formar un [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-mn","format":"standard","meta":{"footnotes":""},"categories":[25],"tags":[66],"class_list":["post-740","post","type-post","status-publish","format-standard","hentry","category-mn-3eva10","tag-raices"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/740","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=740"}],"version-history":[{"count":4,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/740\/revisions"}],"predecessor-version":[{"id":17785,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/740\/revisions\/17785"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=740"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=740"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=740"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}