{"id":819,"date":"2017-12-11T15:30:32","date_gmt":"2017-12-11T20:30:32","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1013\/?p=819"},"modified":"2026-04-05T06:11:11","modified_gmt":"2026-04-05T11:11:11","slug":"3eva2011ti_t1_mn-distribuidor-de-combustible","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/mn-3eva20\/3eva2011ti_t1_mn-distribuidor-de-combustible\/","title":{"rendered":"3Eva2011TI_T1_MN Distribuidor de combustible"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">3ra Evaluaci\u00f3n I T\u00e9rmino 2011-2012. 13\/Septiembre\/2011. ICM02188 M\u00e9todos Num\u00e9ricos<\/h2>\n\n\n\n<p><strong>Tema 1<\/strong>. (30 puntos) Un distribuidor de gasolina llena el dep\u00f3sito al inicio de cada semana. La proporci\u00f3n del contenido que vende semanalmente es una variable <strong>x<\/strong> &nbsp;cuyo valor puede estar entre 0 y 1.<\/p>\n\n\n\n<p>La probabilidad que \u00e9sta variable <strong>x<\/strong> est\u00e9 en alg\u00fan intervalo <strong>[a, b<\/strong>] \u2282 [0, 1] se obtiene integrando entre <strong>a<\/strong> y <strong>b<\/strong> el siguiente modelo<\/p>\n\n\n\n<p class=\"has-text-align-center\">f(x) = 20 x<sup>3 <\/sup>(1+x).<\/p>\n\n\n\n<p>Encuentre el intervalo [0, <strong>b<\/strong>] tal que la probabilidad sea igual a 0.5<\/p>\n\n\n\n<p>Para calcular <strong>b<\/strong> use el <strong>m\u00e9todo de Newton<\/strong>, muestre los valores intermedios.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>3ra Evaluaci\u00f3n I T\u00e9rmino 2011-2012. 13\/Septiembre\/2011. ICM02188 M\u00e9todos Num\u00e9ricos Tema 1. (30 puntos) Un distribuidor de gasolina llena el dep\u00f3sito al inicio de cada semana. La proporci\u00f3n del contenido que vende semanalmente es una variable x &nbsp;cuyo valor puede estar entre 0 y 1. La probabilidad que \u00e9sta variable x est\u00e9 en alg\u00fan intervalo [a, [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-mn","format":"standard","meta":{"footnotes":""},"categories":[28],"tags":[59],"class_list":["post-819","post","type-post","status-publish","format-standard","hentry","category-mn-3eva20","tag-integracion-numerica"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/819","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=819"}],"version-history":[{"count":3,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/819\/revisions"}],"predecessor-version":[{"id":17724,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/819\/revisions\/17724"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=819"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=819"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=819"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}