{"id":834,"date":"2017-12-11T12:31:37","date_gmt":"2017-12-11T17:31:37","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1013\/?p=834"},"modified":"2026-04-05T06:29:54","modified_gmt":"2026-04-05T11:29:54","slug":"2eva2011tii_t3-edp-parabolica-explicito","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/mn-2eva20\/2eva2011tii_t3-edp-parabolica-explicito\/","title":{"rendered":"2Eva2011TII_T3 EDP Parab\u00f3lica expl\u00edcito"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">2da Evaluaci\u00f3n II T\u00e9rmino 2011-2011. 31\/Enero\/2012. ICM00158<\/h2>\n\n\n\n<p><strong>Tema 3<\/strong>. Aproxime la soluci\u00f3n de la ecuaci\u00f3n diferencial parcial:<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> \\frac{\\partial u}{\\partial t} - \\frac{\\partial^2 u}{\\partial x^2} =2<\/span>\n\n\n\n<p class=\"has-text-align-center\">t&gt; 0 , 0\u2264 x \u2264 1<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> \\begin{cases} u(0,t) = u(1,t) = 0, &amp; t\\gt0 \\\\u(x,0) = \\sin (\\pi x) + x(1-x) \\end{cases} <\/span>\n\n\n\n<p>Con <strong>h<\/strong>= 0.25 y <strong>k<\/strong>=0.04, realizar solo dos iteraciones en el tiempo (j=1,2) .<\/p>\n\n\n\n<p><strong>Indicaci\u00f3n:<\/strong> Para establecer el algoritmo, utilice la f\u00f3rmula progresiva para la primera derivada.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>2da Evaluaci\u00f3n II T\u00e9rmino 2011-2011. 31\/Enero\/2012. ICM00158 Tema 3. Aproxime la soluci\u00f3n de la ecuaci\u00f3n diferencial parcial: t&gt; 0 , 0\u2264 x \u2264 1 Con h= 0.25 y k=0.04, realizar solo dos iteraciones en el tiempo (j=1,2) . Indicaci\u00f3n: Para establecer el algoritmo, utilice la f\u00f3rmula progresiva para la primera derivada.<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-mn","format":"standard","meta":{"footnotes":""},"categories":[20],"tags":[57],"class_list":["post-834","post","type-post","status-publish","format-standard","hentry","category-mn-2eva20","tag-edp"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/834","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=834"}],"version-history":[{"count":4,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/834\/revisions"}],"predecessor-version":[{"id":23415,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/834\/revisions\/23415"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=834"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=834"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=834"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}