{"id":858,"date":"2017-12-12T15:00:19","date_gmt":"2017-12-12T20:00:19","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1013\/?p=858"},"modified":"2026-04-05T06:10:00","modified_gmt":"2026-04-05T11:10:00","slug":"3eva2012ti_t1-sistema-ecuaciones-no-lineales","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/mn-3eva20\/3eva2012ti_t1-sistema-ecuaciones-no-lineales\/","title":{"rendered":"3Eva2012TI_T1 Sistema Ecuaciones no lineales"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">3ra Evaluaci\u00f3n I T\u00e9rmino 2012-2013. 11\/Septiembre\/2012. ICM00158<\/h2>\n\n\n\n<p><strong>Tema 1<\/strong>. Dado el sistema de ecuaciones no lineales<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> 3x^2 + 3y^2 - 15 = 0 <\/span>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> 2x^2y- 1 = 0<\/span>\n\n\n\n<p class=\"has-text-align-center\"><em>x<\/em>\u2208R; &nbsp;&nbsp;<em>y&nbsp;<\/em>\u2265 1<\/p>\n\n\n\n<p>a. Realice un bosquejo gr\u00e1fico y especifique el n\u00famero de soluciones del sistema.<\/p>\n\n\n\n<p>b. Determine la ecuaci\u00f3n en t\u00e9rminos de una variable para resolver el sistema.<\/p>\n\n\n\n<p>c. Justifique un intervalo donde se encuentre la soluci\u00f3n de la ecuaci\u00f3n planteada en literal b.<\/p>\n\n\n\n<p>d. Aproxime la soluci\u00f3n empleando el m\u00e9todo de Newton-Raphson con tolerancia de 10<sup>-6<\/sup>.<\/p>\n\n\n\n<p>e. Escriba correctamente la soluci\u00f3n hallada.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>3ra Evaluaci\u00f3n I T\u00e9rmino 2012-2013. 11\/Septiembre\/2012. ICM00158 Tema 1. Dado el sistema de ecuaciones no lineales x\u2208R; &nbsp;&nbsp;y&nbsp;\u2265 1 a. Realice un bosquejo gr\u00e1fico y especifique el n\u00famero de soluciones del sistema. b. Determine la ecuaci\u00f3n en t\u00e9rminos de una variable para resolver el sistema. c. Justifique un intervalo donde se encuentre la soluci\u00f3n de [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-mn","format":"standard","meta":{"footnotes":""},"categories":[28],"tags":[66],"class_list":["post-858","post","type-post","status-publish","format-standard","hentry","category-mn-3eva20","tag-raices"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/858","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=858"}],"version-history":[{"count":3,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/858\/revisions"}],"predecessor-version":[{"id":17740,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/858\/revisions\/17740"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=858"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=858"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=858"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}