{"id":866,"date":"2017-12-12T14:00:49","date_gmt":"2017-12-12T19:00:49","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1013\/?p=866"},"modified":"2026-04-05T05:51:07","modified_gmt":"2026-04-05T10:51:07","slug":"2eva2012ti_t1_mn-longitud-de-teleferico","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/mn-2eva20\/2eva2012ti_t1_mn-longitud-de-teleferico\/","title":{"rendered":"2Eva2012TI_T1_MN Longitud de telef\u00e9rico"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">2da Evaluaci\u00f3n I T\u00e9rmino 2012-2013. 28\/Agosto\/2012. ICM002188<\/h2>\n\n\n\n<p><strong>Tema 1<\/strong>. (40 puntos)<\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"512\" height=\"384\" src=\"http:\/\/blog.espol.edu.ec\/algoritmos101\/files\/2017\/12\/cableTeleferico01.png\" alt=\"cable Telef\u00e9rico aerov\u00eda\" class=\"wp-image-17345\" style=\"width:350px\" \/><\/figure>\n\n\n\n<p>La trayectoria de un telef\u00e9rico est\u00e1 definida por una curva que tiene los puntos (<strong>x<\/strong>, <strong>f<\/strong>(<strong>x<\/strong>)) seg\u00fan la tabla que se muestra a continuaci\u00f3n:&nbsp;<\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>x    = &#091;0.00, 0.25, 0.50, 0.75, 1.00]\nf(x) = &#091;25.0, 22.0, 32.0, 51.0, 75.0] <\/code><\/pre>\n\n\n\n<p>Para calcular la longitud de dicha curva se debe usar la integral:<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> L = \\int_a^b \\sqrt{1+[f'(x)]^2} \\delta x <\/span>\n\n\n\n<p>a. Aproxime el valor de la derivada <strong>f<\/strong>'(x) en todos los puntos de la tabla con f\u00f3rmulas de orden 2.<\/p>\n\n\n\n<p>b. Aproxime el valor de la longitud del cable del telef\u00e9rico entre 0 y 1 con la f\u00f3rmula de Simpson<\/p>\n\n\n\n<p>c. Aproxime el error de la longitud calculada.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>2da Evaluaci\u00f3n I T\u00e9rmino 2012-2013. 28\/Agosto\/2012. ICM002188 Tema 1. (40 puntos) La trayectoria de un telef\u00e9rico est\u00e1 definida por una curva que tiene los puntos (x, f(x)) seg\u00fan la tabla que se muestra a continuaci\u00f3n:&nbsp; Para calcular la longitud de dicha curva se debe usar la integral: a. Aproxime el valor de la derivada f'(x) [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-mn","format":"standard","meta":{"footnotes":""},"categories":[20],"tags":[59],"class_list":["post-866","post","type-post","status-publish","format-standard","hentry","category-mn-2eva20","tag-integracion-numerica"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/866","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=866"}],"version-history":[{"count":7,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/866\/revisions"}],"predecessor-version":[{"id":17356,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/866\/revisions\/17356"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=866"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=866"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=866"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}