{"id":878,"date":"2017-12-14T15:07:52","date_gmt":"2017-12-14T20:07:52","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1013\/?p=878"},"modified":"2026-04-05T05:50:10","modified_gmt":"2026-04-05T10:50:10","slug":"2eva2014tii_t2-edo-carga-uniforme-en-viga","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/mn-2eva20\/2eva2014tii_t2-edo-carga-uniforme-en-viga\/","title":{"rendered":"2Eva2014TII_T2 EDO Carga uniforme en viga"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">2da Evaluaci\u00f3n II T\u00e9rmino 2014-2015. 23\/Febrero\/2015. ICM00158<\/h2>\n\n\n\n<p><strong>Tema 2<\/strong>. La ecuaci\u00f3n diferencial b\u00e1sica de la curva el\u00e1stica para una viga con carga uniforme (ver figura) est\u00e1 dada por<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> EI \\frac{\\delta ^2 y}{\\delta x^2} = \\frac{wLx}{2} - \\frac{wx^2}{2}<\/span>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"571\" height=\"194\" src=\"http:\/\/blog.espol.edu.ec\/algoritmos101\/files\/2017\/12\/cargaUniformeViga01.png\" alt=\"carga Uniforme Viga\" class=\"wp-image-17371\" \/><\/figure>\n\n\n\n<p>Donde E = m\u00f3dulo de elasticidad, I = momento de inercia<\/p>\n\n\n\n<p>Resuelva para la deflexi\u00f3n de la viga con el m\u00e9todo de disparo con <strong>Runge-Kutta de 2do orden<\/strong> y (\u0394x = 2.5 ft).<\/p>\n\n\n\n<p>Aplique los siguientes valores de par\u00e1metros:<br>E = 30.000 ksi<br>I = 800 in<sup>4<br><\/sup>w = 1 kip\/in<br>L = 10 ft.<\/p>\n\n\n\n<p><strong>Referencia<\/strong>: Chapra 5Ed Cap28 Ejercicio 28.23 p849 pdf873.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>2da Evaluaci\u00f3n II T\u00e9rmino 2014-2015. 23\/Febrero\/2015. ICM00158 Tema 2. La ecuaci\u00f3n diferencial b\u00e1sica de la curva el\u00e1stica para una viga con carga uniforme (ver figura) est\u00e1 dada por Donde E = m\u00f3dulo de elasticidad, I = momento de inercia Resuelva para la deflexi\u00f3n de la viga con el m\u00e9todo de disparo con Runge-Kutta de 2do [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-mn","format":"standard","meta":{"footnotes":""},"categories":[20],"tags":[56],"class_list":["post-878","post","type-post","status-publish","format-standard","hentry","category-mn-2eva20","tag-edo"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/878","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=878"}],"version-history":[{"count":2,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/878\/revisions"}],"predecessor-version":[{"id":17372,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/878\/revisions\/17372"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=878"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=878"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=878"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}