{"id":900,"date":"2017-12-15T08:05:19","date_gmt":"2017-12-15T13:05:19","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1013\/?p=900"},"modified":"2026-04-05T05:49:42","modified_gmt":"2026-04-05T10:49:42","slug":"2eva2015ti_t2-deflexion-de-mastil","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/mn-2eva20\/2eva2015ti_t2-deflexion-de-mastil\/","title":{"rendered":"2Eva2015TI_T2 EDO Deflexi\u00f3n de m\u00e1stil"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">2da Evaluaci\u00f3n I T\u00e9rmino 2015-2016. 8\/Septiembre\/2015. ICM00158<\/h2>\n\n\n\n<p><strong>Tema 2<\/strong>. (30 puntos) La ecuaci\u00f3n siguiente se utiliza para modelar la deflexi\u00f3n del m\u00e1stil de un bote expuesto a la fuerza del viento:<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> \\frac{\\delta ^2 y}{\\delta x^2} = \\frac{f}{2EI} (L-x)^2 <\/span>\n\n\n\n<figure class=\"wp-block-image alignright size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"288\" height=\"411\" src=\"http:\/\/blog.espol.edu.ec\/algoritmos101\/files\/2017\/12\/MastilDeflexion.png\" alt=\"M\u00e1stil Deflexi\u00f3n barco\" class=\"wp-image-17385\" \/><\/figure>\n\n\n\n<p>Donde:<br>f = fuerza,<br>E = m\u00f3dulo de elasticidad,<br>L = longitud del m\u00e1stil<br>I = momento de inercia.<\/p>\n\n\n\n<p>Calcule la deflexi\u00f3n si y = 0 y <span class=\"wp-katex-eq\" data-display=\"false\">\\frac{\\delta y}{\\delta x} = 0 <\/span> en x = 0.<\/p>\n\n\n\n<p>Para sus c\u00e1lculos considere <strong>f<\/strong>=60, <strong>L<\/strong> =30, <strong>E<\/strong> = 1.25x10<sup>8<\/sup> e <strong>I<\/strong> = 0.05.<\/p>\n\n\n\n<p>a. Encuentre el sistema de ecuaciones diferenciales equivalente a dicha ecuaci\u00f3n.<\/p>\n\n\n\n<p>b. Aproxime usando Runge-Kutta 4to orden, para <strong>n<\/strong>=30 sub-intervalos. (solo expresado)<\/p>\n\n\n\n<p>c. Aproxime considerando <strong>h<\/strong>=2 y realice 2 pasos usando Runge-Kutta de 2do orden.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\" \/>\n\n\n\n<p><em><strong>Referencias<\/strong><\/em>: Chapra 24.2 p284 pdf121<\/p>\n\n\n\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe loading=\"lazy\" title=\"The Mast Walk by Alex Thomson\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/y4loB_UGxw8?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" referrerpolicy=\"strict-origin-when-cross-origin\" allowfullscreen><\/iframe>\n<\/div><\/figure>\n\n\n\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-4-3 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe loading=\"lazy\" title=\"Horizon Cat Mast Bend\" width=\"500\" height=\"375\" src=\"https:\/\/www.youtube.com\/embed\/67DiGSrHC8M?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" referrerpolicy=\"strict-origin-when-cross-origin\" allowfullscreen><\/iframe>\n<\/div><\/figure>\n\n\n\n<p>&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>2da Evaluaci\u00f3n I T\u00e9rmino 2015-2016. 8\/Septiembre\/2015. ICM00158 Tema 2. (30 puntos) La ecuaci\u00f3n siguiente se utiliza para modelar la deflexi\u00f3n del m\u00e1stil de un bote expuesto a la fuerza del viento: Donde:f = fuerza,E = m\u00f3dulo de elasticidad,L = longitud del m\u00e1stilI = momento de inercia. Calcule la deflexi\u00f3n si y = 0 y en [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-mn","format":"standard","meta":{"footnotes":""},"categories":[20],"tags":[56],"class_list":["post-900","post","type-post","status-publish","format-standard","hentry","category-mn-2eva20","tag-edo"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/900","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=900"}],"version-history":[{"count":2,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/900\/revisions"}],"predecessor-version":[{"id":17386,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/900\/revisions\/17386"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=900"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=900"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=900"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}