{"id":968,"date":"2017-12-17T15:10:23","date_gmt":"2017-12-17T20:10:23","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1013\/?p=968"},"modified":"2025-12-13T09:30:05","modified_gmt":"2025-12-13T14:30:05","slug":"3eva2017ti_t3-sustancia-en-lago","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/mn-3eva20\/3eva2017ti_t3-sustancia-en-lago\/","title":{"rendered":"3Eva2017TI_T3 Sustancia en lago"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">3ra Evaluaci\u00f3n I T\u00e9rmino 2017-2018. 11\/Septiembre\/2017. MATG1013<\/h2>\n\n\n\n<p><strong>Tema 3<\/strong>. El \u00e1rea de la secci\u00f3n transversal As (m<sup>2<\/sup>) de un lago, a cierta profundidad, se calcula a partir del volumen utilizando la diferenciaci\u00f3n:<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> A_s(Z) = -\\frac{\\delta V}{\\delta z} (Z) <\/span>\n\n\n\n<p>Donde V = volumen (m<sup>3<\/sup>) y z = profundidad (m), se mide a partir de la superficie en direcci\u00f3n del fondo.<\/p>\n\n\n\n<p>La concentraci\u00f3n promedio de una sustancia que var\u00eda con la profundidad <span class=\"wp-katex-eq\" data-display=\"false\">\\overline{c}<\/span> (g\/m<sup>3<\/sup>) se obtiene por integraci\u00f3n:<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> \\overline{c} = \\frac{\\int_0^{Z_t} c(Z) A_s(Z) \\delta Z}{\\int_0^{Z_t}A_s(z) \\delta Z} <\/span>\n\n\n\n<p>Donde Z<sub>t<\/sub> es la profundidad total (m).<br>Determine la concentraci\u00f3n promedio con base en los siguientes datos:<\/p>\n\n\n\n<figure class=\"wp-block-table\"><table><tbody><tr><td>z (m)<\/td><td>&nbsp;0<\/td><td>&nbsp;4<\/td><td>8<\/td><td>12<\/td><td>16<\/td><\/tr><tr><td>V (10<sup>6<\/sup> m<sup>3<\/sup>)<\/td><td>&nbsp;9.82<\/td><td>5.11<\/td><td>1.96<\/td><td>0.393<\/td><td>0.000<\/td><\/tr><tr><td>c (g\/m<sup>3<\/sup>)<\/td><td>&nbsp;10.2<\/td><td>&nbsp;8.5<\/td><td>&nbsp;7.4<\/td><td>5.2<\/td><td>4.1<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\" \/>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"530\" height=\"415\" src=\"http:\/\/blog.espol.edu.ec\/algoritmos101\/files\/2017\/12\/SustanciaLago01.png\" alt=\"SustanciaLago01\" class=\"wp-image-17667\" \/><\/figure>\n\n\n\n<pre class=\"wp-block-code\"><code>zi = &#091;0.  , 4   , 8   , 12    , 16]\nvi = &#091;9.82, 5.11, 1.96,  0.393,  0.]\nci = &#091;10.2, 8.5 , 7.4 ,  5.2  ,  4.1]<\/code><\/pre>\n","protected":false},"excerpt":{"rendered":"<p>3ra Evaluaci\u00f3n I T\u00e9rmino 2017-2018. 11\/Septiembre\/2017. MATG1013 Tema 3. El \u00e1rea de la secci\u00f3n transversal As (m2) de un lago, a cierta profundidad, se calcula a partir del volumen utilizando la diferenciaci\u00f3n: Donde V = volumen (m3) y z = profundidad (m), se mide a partir de la superficie en direcci\u00f3n del fondo. La concentraci\u00f3n [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-mn","format":"standard","meta":{"footnotes":""},"categories":[28],"tags":[55],"class_list":["post-968","post","type-post","status-publish","format-standard","hentry","category-mn-3eva20","tag-diferenciacion-numerica"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/968","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=968"}],"version-history":[{"count":3,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/968\/revisions"}],"predecessor-version":[{"id":17669,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/968\/revisions\/17669"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=968"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=968"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=968"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}