{"id":987,"date":"2017-12-16T16:35:54","date_gmt":"2017-12-16T21:35:54","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1013\/?p=987"},"modified":"2025-12-13T03:07:19","modified_gmt":"2025-12-13T08:07:19","slug":"2eva2016tii_t2_mn-integral-volumen","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/algoritmos101\/mn-evalua\/mn-2e20\/2eva2016tii_t2_mn-integral-volumen\/","title":{"rendered":"2Eva2016TII_T2_MN Volumen cacao seco"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">2da Evaluaci\u00f3n II T\u00e9rmino 2016-2017. 14\/Febrero\/2017. ICM02188 M\u00e9todos Num\u00e9rico<\/h2>\n\n\n\n<p><strong>Tema 2<\/strong>.&nbsp; En una bodega de 4 m x 6m, hay una monta\u00f1a de cacao seco listo para empaque. <\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"259\" height=\"193\" src=\"http:\/\/blog.espol.edu.ec\/algoritmos101\/files\/2017\/12\/SecarCacao01.png\" alt=\"Secar Cacao \" class=\"wp-image-17399\" \/><\/figure>\n\n\n\n<p>La tabla indica la altura en metros de la monta\u00f1a sobre el nodo en el plano medido al cent\u00edmetro m\u00e1s cercano.<\/p>\n\n\n\n<figure class=\"wp-block-table\"><table><thead><tr><th>f(x,y)<\/th><th>x=0<\/th><th>x=1<\/th><th>x=2<\/th><th>x=3<\/th><th>x=4<\/th><\/tr><\/thead><tbody><tr><td>y=0<\/td><td>0.38<\/td><td>0.62<\/td><td>0.38<\/td><td>0.08<\/td><td>0.01<\/td><\/tr><tr><td>y=1.5<\/td><td>1.31<\/td><td>2.16<\/td><td>1.31<\/td><td>0.29<\/td><td>0.02<\/td><\/tr><tr><td>y=3<\/td><td>1.02<\/td><td>1.68<\/td><td>1.02<\/td><td>0.23<\/td><td>0.02<\/td><\/tr><tr><td>y=4.5<\/td><td>0.18<\/td><td>0.29<\/td><td>0.18<\/td><td>0.04<\/td><td>0.00<\/td><\/tr><tr><td>y=6<\/td><td>0.01<\/td><td>0.01<\/td><td>0.01<\/td><td>0.00<\/td><td>0.00<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"429\" height=\"352\" src=\"http:\/\/blog.espol.edu.ec\/algoritmos101\/files\/2017\/12\/2Eva_IIT2016_T2_MN_Cacao.png\" alt=\"2Eva_IIT2016_T2_MN_Cacao\" class=\"wp-image-17401\" \/><\/figure>\n\n\n\n<p>Use el m\u00e9todo de Simpson 1\/3 en ambas direcciones para aproximar el volumen V:<\/p>\n\n\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\"> V = \\int_0^4 \\int_0^6 f(x,y)dydx <\/span>\n\n\n\n<p>a) Realice la formulaci\u00f3n del m\u00e9todo indicando los puntos de la cuadr\u00edcula.<\/p>\n\n\n\n<p>b) Estime la cota del error propagado y error total<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\" \/>\n\n\n\n<p><strong>R\u00fabrica<\/strong>: Planteamiento del problema (5 puntos), selecci\u00f3n de m\u00e9todo minimizando cotas de error (5 puntos), integraci\u00f3n en un eje (5 puntos), integraci\u00f3n en el otro eje (5 puntos), Estimaci\u00f3n de errores (5 puntos)<\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>x = &#091; 0.0, 1.0, 2.0, 3.0, 4.0]\ny = &#091; 0.0, 1.5, 3.0, 4.5, 6.0]\n\nfxy  = &#091;&#091;0.38, 0.62, 0.38, 0.08, 0.01],\n        &#091;1.31, 2.16, 1.31, 0.29, 0.02],\n        &#091;1.02, 1.68, 1.02, 0.23, 0.02],\n        &#091;0.18, 0.29, 0.18, 0.04, 0.00],\n        &#091;0.01, 0.01, 0.01, 0.00, 0.00]]<\/code><\/pre>\n","protected":false},"excerpt":{"rendered":"<p>2da Evaluaci\u00f3n II T\u00e9rmino 2016-2017. 14\/Febrero\/2017. ICM02188 M\u00e9todos Num\u00e9rico Tema 2.&nbsp; En una bodega de 4 m x 6m, hay una monta\u00f1a de cacao seco listo para empaque. La tabla indica la altura en metros de la monta\u00f1a sobre el nodo en el plano medido al cent\u00edmetro m\u00e1s cercano. f(x,y) x=0 x=1 x=2 x=3 x=4 [&hellip;]<\/p>\n","protected":false},"author":8043,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"wp-custom-template-entrada-mn","format":"standard","meta":{"footnotes":""},"categories":[20],"tags":[59],"class_list":["post-987","post","type-post","status-publish","format-standard","hentry","category-mn-2e20","tag-integracion-numerica"],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/987","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/users\/8043"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/comments?post=987"}],"version-history":[{"count":3,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/987\/revisions"}],"predecessor-version":[{"id":17402,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/posts\/987\/revisions\/17402"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/media?parent=987"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/categories?post=987"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/algoritmos101\/wp-json\/wp\/v2\/tags?post=987"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}