The rigorous study of limits.

Prove that
lim (3x - 7) = 5.
x→4
0 < x - 4 < δ  →  3x - 7 - 5 < ε
                                       3x - 12 < ε
                                       3 (x - 4) < ε
                                       x - 4 < ε/3




δ = ε/3


  3x - 12 < δ


 




3 (x - 4) <  3δ = ε


D E M O S T R A D O



Posted by Jorge Loy Benítez on noviembre 7th, 2010 | Filed in NO LABELS, please(: | Comment now »








   
		
		
	 



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