{"id":2002,"date":"2017-07-04T21:45:21","date_gmt":"2017-07-05T02:45:21","guid":{"rendered":"http:\/\/blog.espol.edu.ec\/matg1003\/?p=2002"},"modified":"2017-07-04T21:45:21","modified_gmt":"2017-07-05T02:45:21","slug":"cl2-01-transformaciones-lineales","status":"publish","type":"post","link":"https:\/\/blog.espol.edu.ec\/matg1049\/cl2-01-transformaciones-lineales\/","title":{"rendered":"cl3-01. Transformaciones Lineales"},"content":{"rendered":"<p><code><\/code><\/p>\n<hr \/>\n<pre style=\"text-align: justify\"><strong>Definici\u00f3n.<\/strong> Sean <span class=\"wp-katex-eq\" data-display=\"false\">V<\/span> y <span class=\"wp-katex-eq\" data-display=\"false\">W<\/span> espacios vectoriales cualesquiera. Una transformaci\u00f3n lineal <span class=\"wp-katex-eq\" data-display=\"false\">T{:}\\ V\\rightarrow W<\/span> es una funci\u00f3n que asigna a cada vector <span class=\"wp-katex-eq\" data-display=\"false\">v\\in V<\/span> un vector \u00fanico <span class=\"wp-katex-eq\" data-display=\"false\">T(v)\\in W<\/span> y que satisface las siguientes condiciones:\n\n<span class=\"wp-katex-eq\" data-display=\"false\">1)<\/span> <span class=\"wp-katex-eq\" data-display=\"false\">\\forall\\ v_1, v_2\\in V{:}\\ T(v_1+v_2)=T(v_1)+T(v_2)<\/span>.\n<span class=\"wp-katex-eq\" data-display=\"false\">2)<\/span> <span class=\"wp-katex-eq\" data-display=\"false\">\\forall\\ v\\in V,\\ \\forall \\alpha\\in \\mathbb{R}{:}\\ T(\\alpha v)=\\alpha T(v)<\/span>.\n<\/pre>\n<pre style=\"text-align: justify\"><strong>Ejemplo.<\/strong> Sean <span class=\"wp-katex-eq\" data-display=\"false\">V=\\mathbb{C}[a,b]<\/span> y <span class=\"wp-katex-eq\" data-display=\"false\">W=\\mathbb{R}<\/span> espacios vectoriales. Demuestre que la transformaci\u00f3n <span class=\"wp-katex-eq\" data-display=\"false\">T{:}\\ V\\rightarrow W<\/span> definida por <span class=\"wp-katex-eq\" data-display=\"false\">T(f)=\\int_{a}^{b} f(x) dx<\/span> es lineal.<\/pre>\n<p style=\"text-align: justify\"><strong>Soluci\u00f3n.<\/strong><br \/>\n<span class=\"wp-katex-eq\" data-display=\"false\">1)<\/span> <span class=\"wp-katex-eq\" data-display=\"false\">\\forall\\ f, g\\in V{:}\\ T(f+g)=T(f)+T(g)<\/span>.<\/p>\n<p><span class=\"wp-katex-eq katex-display\" data-display=\"true\">\\small{T(f)=\\int_{a}^{b} f(x) dx \\qquad T(g)=\\int_{a}^{b} g(x) dx \\qquad (f+g)(x)=f(x)+g(x)}<\/span><span class=\"wp-katex-eq katex-display\" data-display=\"true\">\\begin{array}{rcl}T(f+g)&amp;=&amp;\\int_{a}^{b} (f+g)(x)dx\\\\T(f+g)&amp;=&amp;\\int_{a}^{b} [f(x)+g(x)]dx\\\\T(f)+T(g)&amp;=&amp;\\int_{a}^{b} f(x) dx + \\int_{a}^{b} g(x) dx\\end{array}<\/span><\/p>\n<p><span class=\"wp-katex-eq\" data-display=\"false\">2)<\/span> <span class=\"wp-katex-eq\" data-display=\"false\">\\forall\\ f\\in V,\\ \\forall \\alpha\\in \\mathbb{R}{:}\\ T(\\alpha f)=\\alpha T(f)<\/span><\/p>\n<p><span class=\"wp-katex-eq katex-display\" data-display=\"true\">\\small{(\\alpha f)(x)=\\alpha f(x) \\qquad T(f)=\\int_{a}^{b} f(x) dx \\Longrightarrow T(\\alpha f)=\\int_{a}^{b} (\\alpha f)(x) dx}<\/span><span class=\"wp-katex-eq katex-display\" data-display=\"true\">\\small{\\int_{a}^{b} (\\alpha f)(x) dx = \\int_{a}^{b} \\alpha f(x) dx = \\alpha \\int_{a}^{b} f(x) dx = \\alpha T(f)}<\/span><\/p>\n<p>Por consiguiente, <span class=\"wp-katex-eq\" data-display=\"false\">T{:}\\ V\\rightarrow W<\/span> es una transformaci\u00f3n lineal.<\/p>\n<p>\u00a0<\/p>\n<p><!-- salto de linea --><\/p>\n<pre style=\"text-align: justify;background-color: white\"><strong>Teorema.<\/strong> Sea <span class=\"wp-katex-eq\" data-display=\"false\">T{:}\\ V\\rightarrow W<\/span> una transformaci\u00f3n lineal entonces:\n\nLa imagen del cero vector de <span class=\"wp-katex-eq\" data-display=\"false\">V<\/span> es el cero vector de <span class=\"wp-katex-eq\" data-display=\"false\">W<\/span>.\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\">T(0_V)=0_W<\/span>\nLa imagen del inverso de <span class=\"wp-katex-eq\" data-display=\"false\">V<\/span> es el inverso de <span class=\"wp-katex-eq\" data-display=\"false\">V<\/span>.\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\">T(-v)=-T(v)<\/span>\nLa transformada de la combinaci\u00f3n lineal es la combinaci\u00f3n lineal de la transformada.\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\">\\small{T(\\alpha_1 V_1 + \\alpha_2 V_2 + ... +\\alpha_n V_n)=\\alpha_1 T(V_1) + \\alpha_2 T(V_2) + ... +\\alpha_n T(V_n)}<\/span><\/pre>\n<pre style=\"text-align: justify\"><strong>Ejemplo.<\/strong> Sea <span class=\"wp-katex-eq\" data-display=\"false\">T{:}\\ \\wp_2 \\rightarrow \\mathbb{R^3}<\/span> una tranformaci\u00f3n lineal tal que:<span class=\"wp-katex-eq katex-display\" data-display=\"true\">\\footnotesize{T(x+1)=\\left(\\begin{array}{r} 1 \\\\ 0\\\\ 1 \\end{array}\\right) \\quad T(x^2 -1)=\\left(\\begin{array}{r} 0 \\\\ 1\\\\ 1 \\end{array}\\right) \\quad T(2x^2+x-2)=\\left(\\begin{array}{r} 1 \\\\ 1\\\\ 0 \\end{array}\\right)}<\/span>Determine <span class=\"wp-katex-eq\" data-display=\"false\">T(ax^2+bx+c)<\/span>.<\/pre>\n<p style=\"text-align: justify\"><strong>Soluci\u00f3n.<\/strong><\/p>\n<p><span class=\"wp-katex-eq katex-display\" data-display=\"true\">T(ax^2+bx+c)=aT(x^2)+bT(x)+cT(1)<\/span><br \/>\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\">\\left\\{ \\begin{array}{rcl}T(x)+T(1)&amp;=&amp;V_1 \\\\ T(x^2)-T(1)&amp;=&amp;V_2 \\\\ 2T(x^2)+T(x)-2T(1)&amp;=&amp;V_3 \\end{array}\\right.<\/span><br \/>\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\">\\left(\\begin{array}{rrr|r} 0 &amp; 1 &amp; 1 &amp; V_1\\\\ 1 &amp; 0 &amp; -1&amp; V_2 \\\\ 2&amp;1&amp;-2&amp;V_3 \\end{array}\\right) \\approx \\left(\\begin{array}{rrr|r} 1&amp;0&amp;-1&amp;V_2 \\\\ 0&amp;1&amp;1&amp;V_1 \\\\ 0&amp;1&amp;0&amp;V_3 -2V_2 \\end{array}\\right) <\/span><\/p>\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\">\\begin{array}{rclcrcc} T(x)&amp;=&amp;V_3 -2V_2 &amp;\\Longrightarrow&amp; T(x)&amp;=&amp;{\\left(\\begin{array}{r} 1 \\\\ -1\\\\ 2 \\end{array}\\right)} \\\\ T(1)&amp;=&amp;V_1 - T(x) &amp;\\Longrightarrow &amp; T(1)&amp;=&amp;{\\left(\\begin{array}{r} 0 \\\\ 1\\\\ 3 \\end{array}\\right)} \\\\ T(x^2)&amp;=&amp;V_2 + T(1) &amp;\\Longrightarrow &amp; T(x^2)&amp;=&amp;{\\left(\\begin{array}{r} 0 \\\\ 2\\\\ 4 \\end{array}\\right)} \\end{array}<\/span>\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\">T(ax^2+bx+c) = a {\\left(\\begin{array}{r} 0 \\\\ 2\\\\ 4 \\end{array}\\right)} + b {\\left(\\begin{array}{r} 1 \\\\ -1\\\\ 2 \\end{array}\\right)} + c {\\left(\\begin{array}{r} 0 \\\\ 1\\\\ 3 \\end{array}\\right)}<\/span>\n<p>Por consiguiente, <span class=\"wp-katex-eq\" data-display=\"false\">T(ax^2+bx+c) = {\\left(\\begin{array}{c} b \\\\ 2a-b+c\\\\ 4a-2b+3c \\end{array}\\right)} <\/span><\/p>\n<p>\u00a0<\/p>\n<p><!-- salto de linea --><\/p>\n<pre style=\"text-align: justify\"><strong>Ejemplo.<\/strong> Se consideran los conjuntos de vectores <span class=\"wp-katex-eq\" data-display=\"false\">R<\/span> y <span class=\"wp-katex-eq\" data-display=\"false\">R'<\/span>, cuyas coordenadas se asocian a los puntos que forman los rombos <span class=\"wp-katex-eq\" data-display=\"false\">ABCD<\/span> y <span class=\"wp-katex-eq\" data-display=\"false\">A'B'C'D'<\/span> como se aprecia en la figura a continuaci\u00f3n:\n\n<img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2141\" src=\"http:\/\/blog.espol.edu.ec\/matg1049\/files\/2017\/07\/10-Set-01.png\" alt=\"\" width=\"320\" height=\"400\" srcset=\"https:\/\/blog.espol.edu.ec\/matg1049\/files\/2017\/07\/10-Set-01.png 616w, https:\/\/blog.espol.edu.ec\/matg1049\/files\/2017\/07\/10-Set-01-240x300.png 240w\" sizes=\"auto, (max-width: 320px) 100vw, 320px\" \/>Si se define <span class=\"wp-katex-eq\" data-display=\"false\">T{:}\\ \\mathbb{R^2}\\rightarrow \\mathbb{R^2}<\/span> como <span class=\"wp-katex-eq\" data-display=\"false\">T(x,y)=(-y,2x)<\/span>, grafique <span class=\"wp-katex-eq\" data-display=\"false\">R''=T(R')<\/span>; adem\u00e1s, verifique que <span class=\"wp-katex-eq\" data-display=\"false\">T<\/span> es una transformaci\u00f3n lineal.\n<\/pre>\n<p style=\"text-align: justify\"><strong>Soluci\u00f3n.<\/strong><br \/>\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\">\\begin{array}{l} {A'=(x,y)=(4,-4)\\longrightarrow T(x,y)=(-y,2x)=(4,8)=A''}\\\\{B'=(x,y)=(6,-4)\\longrightarrow T(x,y)=(-y,2x)=(4,12)=B''}\\\\{C'=(x,y)=(2,-2)\\longrightarrow T(x,y)=(-y,2x)=(2,4)=C''}\\\\{D'=(x,y)=(4,-2)\\longrightarrow T(x,y)=(-y,2x)=(2,8)=D''}\\end{array}<\/span>Por consiguiente, el conjunto de vectores <span class=\"wp-katex-eq\" data-display=\"false\">R''<\/span> tiene como coordenadas los puntos que conforman el rombo <span class=\"wp-katex-eq\" data-display=\"false\">A''B''C''D''<\/span> como se aprecia en la figura a continuaci\u00f3n:<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2159\" src=\"http:\/\/blog.espol.edu.ec\/matg1049\/files\/2017\/07\/10-Set-02.png\" alt=\"\" width=\"320\" height=\"408\" srcset=\"https:\/\/blog.espol.edu.ec\/matg1049\/files\/2017\/07\/10-Set-02.png 362w, https:\/\/blog.espol.edu.ec\/matg1049\/files\/2017\/07\/10-Set-02-236x300.png 236w\" sizes=\"auto, (max-width: 320px) 100vw, 320px\" \/><\/p>\n<p>Para verificar que <span class=\"wp-katex-eq\" data-display=\"false\">T<\/span> es una transformaci\u00f3n lineal, por definici\u00f3n se debe satisfacer las siguientes condiciones:<\/p>\n<p><span class=\"wp-katex-eq\" data-display=\"false\">1)<\/span> <span class=\"wp-katex-eq\" data-display=\"false\">\\forall\\ v_1, v_2\\in V{:}\\ T(v_1+v_2)=T(v_1)+T(v_2)<\/span>.<\/p>\n<p>Sean <span class=\"wp-katex-eq\" data-display=\"false\">v_1=(x,y)<\/span> y <span class=\"wp-katex-eq\" data-display=\"false\">v_2=(x',y')<\/span> dos vectores de <span class=\"wp-katex-eq\" data-display=\"false\">\\mathbb{R^2}<\/span>.<\/br><\/p>\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\">\\begin{array}{rcl} T(v_1+v_2)&amp;=&amp;T((x,y)+(x',y')) \\\\ &amp;=&amp;T(x+x',y+y')\\\\ &amp;=&amp;(-(y+y'),2(x+x')) \\\\ &amp;=&amp;(-y-y',2x+2x') \\\\ &amp;=&amp;(-y,2x)+(-y',2x') \\\\ &amp;=&amp;T(v_1)+T(v_2)\\end{array}<\/span>\n<p><span class=\"wp-katex-eq\" data-display=\"false\">2)<\/span> <span class=\"wp-katex-eq\" data-display=\"false\">\\forall\\ v\\in V,\\ \\forall \\alpha\\in \\mathbb{R}{:}\\ T(\\alpha v)=\\alpha T(v)<\/span>.<\/p>\n<p>Sean <span class=\"wp-katex-eq\" data-display=\"false\">v=(x,y)<\/span> un vector de <span class=\"wp-katex-eq\" data-display=\"false\">\\mathbb{R^2}<\/span> y <span class=\"wp-katex-eq\" data-display=\"false\">\\alpha \\in \\mathbb{R}<\/span>.<\/br><\/p>\n<span class=\"wp-katex-eq katex-display\" data-display=\"true\">\\begin{array}{rcl} T(\\alpha v)&amp;=&amp;T(\\alpha (x,y))\\\\&amp;=&amp;T(\\alpha x,\\alpha y)\\\\&amp;=&amp;(-\\alpha y,2\\alpha x)\\\\&amp;=&amp;\\alpha(-y,2x)\\\\&amp;=&amp;\\alpha T(v)\\end{array}<\/span>\n<p>Por consiguiente, <span class=\"wp-katex-eq\" data-display=\"false\">T<\/span> es una transformaci\u00f3n lineal.\n<\/p>\n<hr \/>\n<p><strong>Enlaces de inter\u00e9s<\/strong><\/p>\n<pre><a href=\"http:\/\/blog.espol.edu.ec\/matg1003\/videos-semana-10\/\">Clase Online<\/a>\n<a href=\"https:\/\/b.socrative.com\/login\/student\/\" target=\"_blank\" rel=\"noopener noreferrer\">Socrative Student<\/a>\n<a href=\"https:\/\/www.sidweb.espol.edu.ec\/\" target=\"_blank\" rel=\"noopener noreferrer\">Plataforma SIDWeb<\/a>\n<a href=\"http:\/\/blog.espol.edu.ec\/matg1003\/referencias-bibliograficas\/\">Referencias Bibliogr\u00e1ficas<\/a><\/pre>\n","protected":false},"excerpt":{"rendered":"<p>Definici\u00f3n. Sean y espacios vectoriales cualesquiera. Una transformaci\u00f3n lineal es una funci\u00f3n que asigna a cada vector un vector \u00fanico y que satisface las siguientes condiciones: . . Ejemplo. Sean y espacios vectoriales. Demuestre que la transformaci\u00f3n definida por es lineal. Soluci\u00f3n. . Por consiguiente, es una transformaci\u00f3n lineal. \u00a0 Teorema. Sea una transformaci\u00f3n lineal &hellip; <a href=\"https:\/\/blog.espol.edu.ec\/matg1049\/cl2-01-transformaciones-lineales\/\" class=\"more-link\">Sigue leyendo <span class=\"screen-reader-text\">cl3-01. Transformaciones Lineales<\/span><\/a><\/p>\n","protected":false},"author":609,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"categories":[1414634],"tags":[],"class_list":["post-2002","post","type-post","status-publish","format-standard","hentry","category-temas-2da-evaluacion"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/blog.espol.edu.ec\/matg1049\/wp-json\/wp\/v2\/posts\/2002","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.espol.edu.ec\/matg1049\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.espol.edu.ec\/matg1049\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/matg1049\/wp-json\/wp\/v2\/users\/609"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/matg1049\/wp-json\/wp\/v2\/comments?post=2002"}],"version-history":[{"count":0,"href":"https:\/\/blog.espol.edu.ec\/matg1049\/wp-json\/wp\/v2\/posts\/2002\/revisions"}],"wp:attachment":[{"href":"https:\/\/blog.espol.edu.ec\/matg1049\/wp-json\/wp\/v2\/media?parent=2002"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/matg1049\/wp-json\/wp\/v2\/categories?post=2002"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.espol.edu.ec\/matg1049\/wp-json\/wp\/v2\/tags?post=2002"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}